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slavikrds [6]
3 years ago
14

The deer population in a certain state park doubles every year. In the year 2010, there were 30 deer in the park. Which function

can be used to determine the population of deer in the state park based on the number of years since 2010? y = 30(2)x y = 302x y = 2x + 30 y = 30x (2)
Mathematics
1 answer:
Gala2k [10]3 years ago
7 0

Answer:

y = 30(2)^x

Step-by-step explanation:

Initial deer population = 30 (in 2010)

Every year, deer population doubles ; this means there is an 100% increase in the population every year ;

Hence, using the exponential growth relation :

Final = initial * (1 + rate)^year

Here,

Final population y ; x years after 2010

Rate = 100% = 1

Hence,

y = 30(1 + 1)^x

y = 30(2)^x

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yaroslaw [1]

QP=24 cm

RS=11.25 cm

QS=18.75 cm

<u>Explanation</u>:

Given that TQ bisects <RTP

therefore(1)

consider ΔRQS and ΔRPT

QS||PT,RP and RT are transversals

(alternate angles)(2)

comparing (1) and (2)

and triangle SQT is isocelus

Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)

Therefore <RQS=<RPT(corresponding angles)

<RSQ=<RTP(corresponding angles)

therefore by AA criterion for similarity

ΔRQS~ΔRPT

According to the property of similar triangles

RQ/RP=RS/RT=QS/PT9/RP=X/30=QS/50\\9/RP=X/30=(30-X)/50\\X/30=(30-X)/50\\50X=30(30-X)\\50X=900-30X\\50X+30X=900\\80X=900\\X=900/80=11.25\\RS=11.25 cm\\QS=30-X=30-11.25\\QS=18.75 cm\\9/RP=X/30\\9/RP=11.25/30\\9*30/11.25=RP\\RP=24 cm

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Answer:

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