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bazaltina [42]
3 years ago
8

A line has a slope of -13. There is a second line that passes through points (-7,-5) and (6,-4) . Would these lines be parallel

, perpendicular or neither ?
Mathematics
1 answer:
Elza [17]3 years ago
3 0
<h3>Answer: The lines are perpendicular</h3>

=================================================

Work Shown:

Use the slope formula to find the slope of the line through the two given points.

m = (y2 - y1)/(x2 - x1)

m = (-4 - (-5))/(6 - (-7))

m = (-4 + 5)/(6 + 7)

m = 1/13

The slope of the line through the two given points is 1/13.

This is not equal to -13, which was the slope of the first line, so the two lines are not parallel.

However, the two lines are perpendicular because multiplying the two slope values leads to -1

(slope1)*(slope2) = (-13)*(1/13) = -1

note: It might help to think of -13 as -13/1 to help multiply the fractions.

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Answer:

<em>The missing number in Sari's factorization is </em><em>3</em><em>.</em>

Step-by-step explanation:

The given polynomial is,

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Comparing this to the given expression, the missing number in Sari's factorization is 3.

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It is wider and shifted 3 units to the left , Option A is the right answer.

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