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goblinko [34]
3 years ago
10

A cell phone weighs about 2.8 times 10 Superscript n pounds. Which value of n is most reasonable? Negative 3 Negative 1 0 1

Mathematics
2 answers:
Verizon [17]3 years ago
7 0

Answer:

-1

Step-by-step explanation:

The weight of the cell phone is given by:

W=2.8*10^n

The options provided for 'n' are:

a. -3

b. -1

c. 0

d. 1

Applying the possible values:

W_a=2.8*10^{-3}\\W_a = 0.0028\ pounds\\\\W_b=2.8*10^{-1}\\W_b = 0.28\ pounds\\\\W_c=2.8*10^{0}\\W_c = 2.8\ pounds\\\\W_d=2.8*10^{1}\\W_d = 28\ pounds

A cellphone could not possibly weigh as little as 0.0028 or as much as 2.8 or 28 pounds. Therefore, the most reasonable value for n is -1.

EastWind [94]3 years ago
3 0

Answer:

(B)-1

Step-by-step explanation:

Let us plug in the given values into 2.8X10^n2.8X10^{-3}=2.8X 0.001=0.0028\:Pounds\\2.8X10^{-1}=2.8X 0.1=0.28\:Pounds\\2.8X10^{0}=2.8X 1=2.8\:Pounds\\2.8X10^{1}=2.8X 10=28\:Pounds

A reasonable value for the weight of a cell phone will be <u>0.28 Pounds.</u>

Therefore, n=-1

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Aloiza [94]

The perimeter of the kite is (10 + 2√53) units if the kite and the coordinates of the kite are point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

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The figure is missing.

On a coordinate plane, kite WXYZ is shown (please refer to the picture)

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Point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

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Thus, the perimeter of the kite is (10 + 2√53) units if the kite and the coordinates of the kite are point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

Learn more about the quadrilateral here:

brainly.com/question/6321910

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