All categories

4 years ago

Factor out the coefficient of the variable 3f 5

1 answer:

algol134 years ago

5 0

3f5 Changes made to your input should not affect the solution:

(1): "f5" was replaced by "f^5". final result 
3f5

You might be interested in

When you are determining The probability of an event why must the probability be between 0 and 1

bogdanovich [222]

Answer:

either there's a zero percent chance or a 100 percent chance.

every answer will be between 0.00 and 1.00

Step-by-step explanation:

4 0

4 years ago

.6(7 + 3b) remind me how to solve this please

Natalija [7]

Answer: 42 + 18b

Hello!

____________________-

6(7 + 3b) =

42 + 18b

Step-by-step explanation: Simplify the expression.

Hope this helped you!

6 0

3 years ago

Read 2 more answers

Lisa drove 240 miles, then increased her speed by 20 miles per hour for 540 miles. If the second part of the drive took 3 hours

Sever21 [200]

Let u be speed while Lisa drove 240 miles and t be the time in completing 240 miles.

We have been given that Lisa increased her speed 20 mph than initial speed over next 540 miles. So her speed on next 540 miles will be $u+20$ mph.

Further more we are given that she took 3 hours more to complete the next 540 miles of the trip than she took in completing initial 240 miles. So she took $(t+3)$ hours in completing next 540 miles.

Since we know $\text{Speed}=\frac{\text{Distance}}{\text{Time}}$

Now we will substitute our given values in our equation and find out the unknowns. After substitution we will get two equations and two unknowns.

$u=\frac{240}{t}.........(1)\\
\\
(u+20)=\frac{540}{t+3}........(2)$

Now we will substitute equation 1 in equation 2

$(\frac{240}{t}+20)=\frac{540}{t+3}$

Upon solving this equation, we get

$t=6$

Therefore, total time for Lisa to complete the entire trip is 6+6+3 = 15 hours.

And we know that total distance covered is 240+540 = 780 miles

Hence, average speed

$=\frac{\text{Total Distance}}{\text{Total Time}} = \frac{780}{15} = 52 \text{ miles per hour}$

6 0

3 years ago

A test taker gets 70 on 1st exam, 80 on 2nd exam, 2/3 of 4/5 of his 2nd exam on his 3rd test. If the professor gives 5 points ex

Serga [27]

<h3>Answer: 127</h3>

=================================================

Explanation:

The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.

The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.

Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.

So we have these scores

first exam = 70
second exam = 80
third exam = 43
fourth exam = x+5

Adding up these scores and dividing by 4 will get us the average

(sum of scores)/(number of scores) = average

(70+80+43+x+5)/4 = 80

(x+198)/4 = 80

x+198 = 4*80

x+198 = 320

x = 320 - 198

x = 122

So the student got a score of x+5 = 122+5 = 127 on the fourth exam.

7 0

3 years ago

Help help help help help

Dmitriy789 [7]

25/4
You can multiply by crossing
10/24 and x/15
10*15 = 24x
150/24=x
Divide the numerator and denominator by 6
25/4
25/4 is the answer

6 0

3 years ago