If the factors of function f are (x − 6) and (x − 1), what are the zeros of function f?
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We know that the trigonometric identity that uses the adjacent side and the hypotenuse is cosine. We can set this up as:
We need to solve for x, so let's isolate it:
So, x = 10.2 units
We need to solve for x, so let's isolate it:
So, x = 10.2 units
So firstly, <u>the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.</u>
So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:
Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now we can rewrite this expression as<u> , which is your final answer.</u>