Answer:
Step-by-step explanation:
hello :
16t²+120 = y
16t² = y -120 so : t² = (y-120)/16
if : y-120 ≥ 0 t = ±√((y-120)/16)
Answer:
A) Slope = -2 and y-int = 1
Step-by-step explanation:
The easiest way to get the slope and y-intercept from an equation is to put it in slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.
So, let's subtract 8x from both sides, leaving 4y on the left side:
8x + 4y = 4 -> 4y = -8x + 4
Now, let's divide both sides by 4, so that we can have just y on the left side:
y = -2x + 1
-2 is the slope, and 1 is the y-intercept.
Refrection of point (0, 0) across y = 3 gives point (0, 6)
Refrection of point (0, -6) across the x-axis gives point (0, -6)
Answer:
(- 1, - 2 )
Step-by-step explanation:
Given the 2 equations
x - 3y = 5 → (1)
5x - 2y = - 1 → (2)
Rearrange (1) expressing x in terms of y by adding 3y to both sides
x = 5 + 3y → (3)
Substitute x = 5 + 3y in (2)
5(5 + 3y) - 2y = - 1 ← distribute left side
25 + 15y - 2y = - 1
25 + 13y = - 1 ( subtract 25 from both sides )
13y = - 26 ( divide both sides by 13 )
y = - 2
Substitute y = - 2 in (3) for corresponding value of x
x = 5 + (3 × - 2) = 5 - 6 = - 1
Solution is (- 1, - 2 )
