Answer:
Probability that the proportion of airborne viruses in a sample of 529 viruses would be greater than 8% is 0.9545.
Step-by-step explanation:
For the given population the distribution of air-borne viruses is given as 6%. Now for this the value of Z score is given as

Here
is the sample measure which is 8% or 0.08- p is the population measure which is 6% or 0.06
- n is the number of samples which is 529
So the Z score is given as

For this the score, the value of probability is calculated from the table as below:

Here value of p(Z<-1.6955) is given as 0.0455

Since the sum of the angles of a triangle is 180 degrees, we simply have to add all the angles and equate it to 180 to solve for x. So:
100 + 12x + 4 + 14x - 2 = 180
26x = 78
x = 3
So, x is equal to 3.
Answer:
89 seats are not being used
Step-by-step explanation:
You subtract the seats being used by teachers
342 - 75 =267
Change 2/3 into a percentage = 66.6%
Find 66.6% of 267= 177.8 (I rounded up to 178)
Then subtract 177.8/178 from 267 to find the amount of seats not being used.
The amount of seats not being used would come down to 89 seats.
I hope this helps!
Since the events are independent and can be reduced to two outcomes, we can solve it using the binomial formula.