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alukav5142 [94]

2 years ago

12

-6 divided by ( - 2/3) times (-5)

2 answers:

tatuchka [14]2 years ago

7 0

<h3><em><u>Answer:-6 divided by ( - 2/3) times(-5)</u></em></h3>

<h3>Step-by-step explanation:-<em><u>45 </u></em></h3><h3><em><u /></em></h3><h3> Negative Six divided by negative two thirds times negative five equals -45 ... O_O</h3>

musickatia [10]2 years ago

7 0

Exact form :
9/5

decimal form:
1.8

mixed number form:
1 4/5

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−3t≥39 What is the answer

Daniel [21]

Answer:

-3t ≥39

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2 years ago

Can somebody please help me with this math question

nata0808 [166]

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Step-by-step explanation:

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3 years ago

F(v)=6+v^2 how do I solve

Nostrana [21]

Step-by-step explanation:

Well, this is a function. In order to solve this, you need a v value. Once you get a v value, you can plug into into 6+v^2 and wala- you get your answer.

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6 0

3 years ago

Use vieta's theorem to solve the problems.

Mnenie [13.5K]

Using Vieta's Theorem, it is found that c = 72.

<h3>What is the Vieta Theorem?</h3>

Suppose we have a quadratic equation, in the following format:

$y = ax^2 + bx + c$

The roots are p and q.

The Theorem states that:

$p + q = -\frac{b}{a}$

$pq = \frac{c}{a}$

In this problem, the polynomial is:

$x^2 - 17x + c$

Hence the coefficients are $a = 1, b = -17$ .

Since the difference of the solutions is 1, we have that:

$p - q = 1$

$p = 1 + q$

Then, from the first equation of the Theorem:

$p + q = -\frac{b}{a}$

$1 + q + q = 17$

$2q = 16$

$q = 8$

$p = 1 + q = 9$

Now, from the second equation:

$pq = \frac{c}{a}$

$72 = c$

$c = 72$

To learn more about Vieta's Theorem, you can take a look at brainly.com/question/23509978

6 0

2 years ago

The function f(x)= square root of x is translated using the rule (x, y) → (x – 6, y + 9) to create A(x). Which expression descri

Alex73 [517]

The function $f(x)=\sqrt{x}$ is translated according to the rule

$(x,y)\rightarrow (x-6,y+9).$

This translation is translation 6 units to the left and 9 units up.

1. Translation of the function $f(x)=\sqrt{x}$ 6 units to the left gives you the function $g(x)=\sqrt{x+6}.$

2. Translation of the function $g(x)=\sqrt{x+6}$ 9 units up gives you the function $A(x)=\sqrt{x+6}+9.$

The domain of the function $A(x)$ is $[-6,\infty),$ then the range of the function $A(x)$ is $[9,\infty).$

Answer: $[9,\infty).$

4 0

3 years ago