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Montano1993 [528]
2 years ago
13

how many ways can 8 distinguishable books be placed in 5 distinguishable shelves so that each shelf contains one book

Mathematics
1 answer:
musickatia [10]2 years ago
5 0

There are 6720 ways by 8 distinguishable books be placed in 5 shelves.

According to statement

The number of books (n) is 8

The number of shelves (r) is 5

Now, we find the ways by which the 8 books be placed in 5 distinguishable shelves

From Permutation formula

P(n,r) = n! / (n-r)!

Substitute the values then

P(n,r) = 8! / (8-5)!

P(n,r) = (8*7*6*5*4*3*2*1) / (3*2*1)

P(n,r) = 8*7*6*5*4

P(n,r) = 6720

So, there are 6720 ways by 8 distinguishable books be placed in 5 shelves.

Learn more about PERMUTATION here brainly.com/question/11732255

#SPJ4

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Answer:

P=40(1.03526)^{t}

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

P=P_o(1+r)^{t}

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

The initial number of bacteria is Po=40 and it doubles (P=2Po) at t=20 min. With that point we can find the value of r:

2P_o=P_o(1+r)^{20}

Simplifying:

(1+r)^{20}=2

Solving for 1+r:

1+r=\sqrt[20]{2}

1+r=1.03526

The exponential function that models the situation is:

\mathbf{P=40(1.03526)^{t}}

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