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3 years ago

Which mathematical symbol would best fill in the blank to compare the two real numbers?

Mathematics

1 answer:

VikaD [51]3 years ago

5 0

1st option, <

sqroot of 7 is 2.6, 14/5 is 2.8.

2.8 is bigger than 2.6

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Y=2x+10 y=x+1 solve using substitution

Anvisha [2.4K]

Answer:

x = -9

y = -8

Step-by-step explanation:

here's the solution :-

=》y = 2x + 10

=》y = x + 1

plunging the value of y from equation 1 into equation 2

=》2x + 10 = x + 1

=》2x - x = 1 - 10

=》x = -9

value of x = -9

now, plugging the value of x in equation 2, we get :-

=》y = x + 1

=》y = -9 + 1

=》y = -8

6 0

2 years ago

A sixth number will be added to the list. What must it be in order for the mean to be 12?

Nataliya [291]

The sixth number should be 16 in order for the mean to be 12

7 0

3 years ago

Read 2 more answers

1+1 equals what i don't know big prize i give all my brainy points i just graduated don't need this anymore

Marina86 [1]

$\huge \mathbb \pink{HELLO }$

$\sf \green{1 + 1 \: is \: 2}$

$\huge \mathcal \orange{HAVE \: A \: GOOD \: DAY }$

6 0

1 year ago

Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'.

lukranit [14]

The x-coordinates of $\triangle S'T'U'$ will be the negation of the x-coordinates of $\triangle STU$

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for $\triangle STU$ and $\triangle S'T'U'$

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of $\triangle STU$ are

$S = (4,5)$

$T = (5,9)$

$U=(3,8)$

Refer to attachment for illustrations

(1) Reflect $\triangle STU$ over y-axis and describe the transformation

To reflect $\triangle STU$ across the y-axis, the following rule must be followed

$(x,y) \to (-x,y)$

This means that:

$S = (4,5) \to S' = (-4,5)$

$T = (5,9) \to T' = (-5,9)$

$U=(3,8) \to U'=(-3,8)$

The description of the transformation is as follows:

Notice that the signs of the x-coordinates $\triangle STU$ and $\triangle S'T'U'$ of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

(2) Compare the segments and the line of reflection

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

$S = |4| = 4$

The distance between S' and the y-axis is:

$S' = |-4| = 4$

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

From T and T' to the y-axis is:

$T =|5| =5$

$T' =|-5| =5$