Answer:
a)
a1 = log(1) = 0 (2⁰ = 1)
a2 = log(2) = 1 (2¹ = 2)
a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849
a4 = log(4) = 2 (2² = 4)
a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322
a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)
a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807
a8 = log(8) = 3 (2³ = 8)
a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )
a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322
b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:
log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that
a1 = 1
a2 = 2
a3 = 3
a4 = 4
a5 = 5
a6 = 6
a7 = 7
a8 = 8
a9 = 9
a10 = 10
I hope this works for you!!
Answer:
1759.52cm^3
Step-by-step explanation:
Given data
Cylinder E
h = 30 cm and
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*30
V= 3.142*16*30
V=1508.16 cm^3
Cylinder F
h=5 cm
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*5
V= 3.142*16*5
V=251.36 cm^3
Hence the total volume is
=251.36+1508.16
= 1759.52cm^3
Answer:
Step-by-stnxnep explanation:
Answer:
18149.20
Step-by-step explanation:
Answer:
go left 2 and up 6
Step-by-step explanation:
(x,y)
(x,y) --> (-2,6)
0 = x 0 = y
0 - 2 = -2 = x
0 + 6 = 6 = y
(-2,6)
When making the X negative, you want to go left on the grid. When making Y positive, you want to go up on the grid.
