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Fudgin [204]
4 years ago
14

Idk the answer to this question please help me

Mathematics
1 answer:
erica [24]4 years ago
7 0
2/3 x 42/3
hope this helps

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Please help this is all the points i got
Westkost [7]

Answer:

2nd page number 2

Step-by-step explanation:

They are both straight lines? Sorry if thats not what you wanted or if its wrong

8 0
2 years ago
Solve for y. 14y-6(y-3)=22
mario62 [17]

Answer:

y=0.5

Step-by-step explanation:

14y-6(y-3)=22

14y-6y+18=22

8y+18=22

8y=4

y=0.5

Then we check our work...

14(0.5)-6((0.5)-3)=22

7-6(-2.5)=22

7+15=22

7+15 does equal 22, so this solution is correct.

3 0
3 years ago
2 sin^2 + sin x - 3 = 0
denpristay [2]

Answer:

x = 2 π n_1 + π/2 for n_1 element Z

or x = π + sin^(-1)(3/2) + 2 π n_2 for n_2 element Z or x = 2 π n_3 - sin^(-1)(3/2) for n_3 element Z

Step-by-step explanation:

Solve for x:

-3 + sin(x) + 2 sin^2(x) = 0

The left hand side factors into a product with two terms:

(sin(x) - 1) (2 sin(x) + 3) = 0

Split into two equations:

sin(x) - 1 = 0 or 2 sin(x) + 3 = 0

Add 1 to both sides:

sin(x) = 1 or 2 sin(x) + 3 = 0

Take the inverse sine of both sides:

x = 2 π n_1 + π/2 for n_1 element Z

or 2 sin(x) + 3 = 0

Subtract 3 from both sides:

x = 2 π n_1 + π/2 for n_1 element Z

or 2 sin(x) = -3

Divide both sides by 2:

x = 2 π n_1 + π/2 for n_1 element Z

or sin(x) = -3/2

Take the inverse sine of both sides:

Answer:  x = 2 π n_1 + π/2 for n_1 element Z

or x = π + sin^(-1)(3/2) + 2 π n_2 for n_2 element Z or x = 2 π n_3 - sin^(-1)(3/2) for n_3 element Z

3 0
3 years ago
Need help fast will give brainiest
Elan Coil [88]

Answer:

\text{1. }\triangle IJH\cong \triangle LKM, \\\text{2. }\triangle RST\cong \triangle YXZ, \\\text{3a. Reflexive Property}, \\\text{3b. ASA (Angle-Side-Angle)}

Step-by-step explanation:

ASA (Angle-Side-Angle) is a proof of congruence that states if two triangles share two angles and the side between those two angles, the triangles are congruent. In problems 1 and 2, the following demonstrate this:

\text{1. }\triangle IJH\cong \triangle LKM, \\\text{2. }\triangle RST\cong \triangle YXZ

In problem 3, \overline{IJ}\cong \overline{IJ} is known in geometry as the Reflexive Property. Because of this, the two triangles in the diagram for problem 3 now share two angles and the side between them, thus they are congruent from ASA (Angle-Side-Angle).

6 0
3 years ago
213,415.16 in expanded form
weqwewe [10]
200,000 + 10,000 + 3,000 + 400 + 10 + 6 + 0.1 + 0.06
8 0
3 years ago
Read 2 more answers
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