Answer:
price for senior citizen is $11
price for child ticket is $8
A) Demand function
price (x) demand (D(x))
4 540
3.50 810
D - 540 810 - 540
----------- = -----------------
x - 4 3.50 - 4
D - 540
----------- = - 540
x - 4
D - 540 = - 540(x - 4)
D = -540x + 2160 + 540
D = 2700 - 540x
D(x) = 2700 - 540x
Revenue function, R(x)
R(x) = price * demand = x * D(x)
R(x) = x* (2700 - 540x) = 2700x - 540x^2
b) Profit, P(x)
profit = revenue - cost
P(x) = R(x) - 30
P(x) = [2700x - 540x^2] - 30
P(x) = 2700x - 540x^2 - 30
Largest possible profit => vertex of the parabola
vertex of 2700x - 540x^2 - 30
When you calculate the vertex you find x = 5 /2
=> P(x) = 3345
Answer: you should charge a log-on fee of $2.5 to have the largest profit, which is $3345.
Answer: 9 in
Step-by-step explanation:
Answer:
It would be <u>97.50</u> square deckles.
Step-by-step explanation:
Given:
On the distant plant, Mathology, a sports area covers 7400 yodels².
1 deckle = 75.9 yodels.
Now, to get the square deckles.
As given, 1 deckle = 75.9 yodels.
So, to get the square deckles by using conversion factor:
<em>75.9 yodels = 1 deckle.</em>
7400 yodels² = 
= 
Therefore, it would be 97.50 square deckles.
