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tangare [24]
3 years ago
11

A polynomial function, f(x), with rational coefficients has roots of –2 and square root of 3. The irrational conjugates theorem

states that which of the following must also be a root of the function?
Mathematics
2 answers:
kap26 [50]3 years ago
8 0

Answer:

Step-by-step explanation:

option b

makkiz [27]3 years ago
4 0

Answer:if 2 + √3 is an irrational root to a polynomial, then its irrational conjugate 2- √3 is also.

Step-by-step explanation:

Given : A polynomial function, f(x), with rational coefficients has roots of –2 and square root of 3.

To find :  which of the following must also be a root of the function?

Solution : We have root of  f(x)  = 2 +√3.

By the  irrational conjugates theorem : it state that  states that if   a + √b is an irrational root to a polynomial, then its irrational conjugate a - √b is also

root.

Therefore, if 2 + √3 is an irrational root to a polynomial, then its irrational conjugate 2- √3 is also.

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