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3 years ago

Can you please help me with this?

Mathematics

1 answer:

Dimas [21]3 years ago

4 0

Just substitute the coordinates

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I NEED HELP PLEASE!!

Anna71 [15]

Answer:

m = 2

Step-by-step explanation:

take 2 pairs from x

choose (1,5) and (2,7)

it will be m = 5 - 7

and in the bottom 1 - 2 it's a fraction

m = -2/-1

the numerator and denominator can't be both negative

so your answer is m= +2

m= slope

rate of change= slope

7 0

2 years ago

A=12h(b1+b2) solve for b1 please.

Papessa [141]

A = 12h(B1 + B2)
A = 12h(B1) + 12h(B2)
A - 12h(B2) = 12h(B1)

B1 = $\frac{A - 12h(B1)}{12h}$

6 0

2 years ago

10v2 + 50

Svetach [21]

Answer:

what is the question? probably describe the polynomial. okay. the polynomial 10v^2 + 50 is a quadratic (it is to the 2nd power) and a binomial (has 2 terms).

7 0

2 years ago

The Edward James Toy Company uses a Kanban system to make plastic wheels that are a component of several toys. The waiting time

pickupchik [31]

Answer:

$N_c \approx 5.0$

Step-by-step explanation:

From the question we are told that:

Waiting time for a container of the wheels during production $T_w=0.25day$

Average processing time is $T_a=0.15 day per container$

Wheel per container $N_w=200$

Total wheel per day $D=2000$

Policy variable of $X=5%$

Generally the equation for Total number of container $N_c$ is mathematically given by

$N_c=DT(\frac{1+X}{N_w} )$

Where

Total time $T=T_w+T_a$

$T=0.15+0.25$

Therefore

$N_c=DT(\frac{1+X}{N_w} )$

$N_c=2000*0.40(\frac{1+0.5}{200} )$

$N_c=(\frac{840}{200} )$

$N_c=4.2$

$N_c \approx 5.0$

Therefore the number of Kanban containers needed for the wheels is

$N_c \approx 5.0$

3 0

2 years ago

What is the difference between a repeating decimal and a terminating decimal?

Pani-rosa [81]

Answer:

Terminating decimals have a finite number of digits after the decimal point while Repeating decimals have one or more numbers or sequences of repeating numbers after the decimal point.

If you found this helpful please give me branliest.

8 0

3 years ago