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Ray Of Light [21]
3 years ago
12

Can you please help me with this?

Mathematics
1 answer:
Dimas [21]3 years ago
4 0
Just substitute the coordinates
You might be interested in
Solve the quadratic function using square root X+10x+25 =18
lawyer [7]

Answer:

= − 7 /1 1  in fraction form

Step-by-step explanation:

STEP 1: Multiply by 1

1 + 1 0 + 2 5 = 1 8

+ 1 0 + 2 5 = 1 8                                                                                                                               STEP 2: Combine like terms

+ 1 0 + 2 5 = 1 8

1 1 + 2 5 = 1 8                                                                                                                       STEP 3: Subtract  2 5   from both sides of the equation

11x+25=18

1 1 + 2 5 − 2 5 = 1 8 − 2 5

STEP 4: Simplify  by subtracting the numbers

1 1 + 2 5 − 2 5 = 1 8 − 2 5

11x+25−25=18−25                                                                                                   1 1 = 1 8 − 2 5                                                                                                                                   1 1 =  -7

STEP 5: Divide both sides of the equation by the same term                                                     1 1 = − 7                                                                                                                         11x/ 11x = −7/ 1 1 (set up as a fraction)                                                                       STEP 6: Cancel terms that are in both the numerator and denominator

=  − 7 /1 1                                                                                                                      SOLUTION

=  − 7 /1 1

5 0
3 years ago
I need help with now please help
Zinaida [17]
I am pretty sure it is 120 or 30
6 0
3 years ago
Of the 20 flash bulbs in a box, 2 are defective. an inspector will select 2 light bulbs simultaneously and at random from the bo
Shkiper50 [21]

|\Omega|=C(20,2)=\dfrac{20!}{2!18!}=\dfrac{19\cdot20}{2}=190\\
|A|=C(18,2)=\dfrac{18!}{2!16!}=\dfrac{17\cdot18}{2}=153\\\\
P(A)=\dfrac{153}{190}\approx81\%

4 0
3 years ago
A triangular section of land is fenced off due to contamination. Two sides of the triangle are each 16 meters ( 16m) longer than
Sphinxa [80]

Answer: the shortest side is 30m

Step-by-step explanation:

Let the shortest side be a meters

If side 2 is 16m longer than the shortest side, then it is (16+a)meters.

The same goes with side 3.

Then,

a + (16+a) + (16+a) = 122m

32 + 3a = 122m

Collecting like terms together,

3a = 122 - 32

3a = 90

Divide by coefficient of a

3a/3 = 90/3

a = 30 meters

Check:

30 + (16+30) + (16+30)

30 + 46 + 46 = 112

8 0
3 years ago
Read 2 more answers
(HURRY! I'M BEING TIMED)Write the partial fraction decomposition of the rational expression.
Aleonysh [2.5K]

Answer:

The partial fraction decomposition is \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}.

Step-by-step explanation:

Partial-fraction decomposition is the process of starting with the simplified answer and taking it back apart, of "decomposing" the final expression into its initial polynomial fractions.

To find the partial fraction decomposition of \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}:

First, the form of the partial fraction decomposition is

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{A}{x + 1}+\frac{B}{\left(x + 1\right)^{2}}+\frac{C}{x + 2}

Write the right-hand side as a single fraction:

                             \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B}{\left(x + 1\right)^{2} \left(x + 2\right)}

The denominators are equal, so we require the equality of the numerators:

             - 4 x^{2} + 13 x - 12=\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B

Expand the right-hand side:

           - 4 x^{2} + 13 x - 12=x^{2} A + x^{2} C + 3 x A + x B + 2 x C + 2 A + 2 B + C

The coefficients near the like terms should be equal, so the following system is obtained:

\begin{cases} A + C = -4\\3 A + B + 2 C = 13\\2 A + 2 B + C = -12 \end{cases}

Solving this system, we get that A=50, B=-29, C=-54.

Therefore,

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}

7 0
3 years ago
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