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OlgaM077 [116]
3 years ago
11

The cost of a taxi ride is represented by the function c(m)=2m+4, where m is the number of miles traveled. What is the cost per

mile of the cab?
$2
$8
$6
$4

Mathematics
2 answers:
deff fn [24]3 years ago
8 0

Answer:

$6

Step-by-step explanation:

We have: The cost of a taxi ride is represented by the function c(m)=2m+4

Plug 1 mile into "m" of the function c(m)=2m+4

So, we have c (1) = 2 ˣ 1 + 4 = 6

Thus, The cost per mile of the cab is $6.

Sergio039 [100]3 years ago
4 0

Answer:

It is 2

Step-by-step explanation:

I took the test

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Find the equation of a line tangent to the circle x2+(y−3)2=34 at the point (5, 0).
salantis [7]

Answer:

Step-by-step explanation:

In order to find the equation of the line tangent to that circle, we have to find the derivative by implicit differentiation which will give us the slope formula of that tangent line.  Let's begin by expanding through the parenthesis to get the standard form of the circle:

x^2+y^2-6y+9=34

Moving the 9 to the other side since the derivative of a constant is 0 gives us

x^2+y^2-6y=25

By implicit differentation, the derivative of that function is

2x+2y\frac{dy}{dx}-6\frac{dy}{dx}=0

To find the derivative, we have to solve for dy/dx:

2y\frac{dy}{dx}-6\frac{dy}{dx}=-2x

Factor out the dy/dx to get:

\frac{dy}{dx}(2y-6)=-2x

Now divide to get your slope formula (first derivative):

\frac{dy}{dx}=\frac{-2x}{2y-6}

Now we can sub in the x and y values from the coodinate to get the slope of that tangent line:

\frac{dy}{dx}=\frac{-2(5)}{2(0)-6}=\frac{-10}{-6}=\frac{5}{3}

So now that have the slope, we can use the point-slope form of a line to write the equation of the tangent line.  The point-slop form of a line is:

y-y₁ = m(x-x₁)

Filling in we get:

y - 0 = 5/3(x - 5) so the equation of the tangent line is:

y=\frac{5}{3}x-\frac{25}{3}

Good luck in your calculus class!

3 0
3 years ago
5[3(x+4)-2(1-x)]-x-15=14x+55 what is x
Nostrana [21]

Answer:

x=2

Step-by-step explanation:

I hope you will understand the way I solved it

if not, dont hesitate to ask questions in the comments...

4 0
3 years ago
On a trip to Griffith Observatory, Dave rode his bicycle six more than twice as many miles in the afternoon as in the morning. I
podryga [215]

Answer:

Dave rode his bicycle 17 miles in the morning

Dave rode his bicycle 40 miles in the afternoon

Step-by-step explanation:

* Lets study the information to solve the question

- Dave rod his bicycle in the morning and again in the afternoon

- Six more than twice as many miles in the afternoon as in the morning

  means the distance in the afternoon is 6 more than twice the distance

  in the morning

- The entire trip was 57 miles means the total distance in the morning

  and in the afternoon was 75

* To solve the question let the distance in the morning is x miles

∵ The distance in the morning = x miles

∵ The distance in the afternoon is 6 more than twice the distance

  in the morning

∴ The distance in the afternoon = 2x + 6 miles

∵ The distance in entire trip = 57 miles

- The distance in the morning and the distance in the afternoon = 57 miles

∴ x + (2x + 6) = 57 ⇒ simplify

∴ 3x + 6 = 57 ⇒ subtract 6 from both sides

∴ 3x = 51 ⇒ divide both sides by 3

∴ x = 17 miles

∵ The distance in the morning is x miles

∴ Dave rode his bicycle 17 miles in the morning

∵ The distance in the afternoon = 2x + 6 miles

- Substitute the value of x

∴ The distance in the afternoon = 2(17) + 6 = 34 + 6 = 40 miles

∴ Dave rode his bicycle 40 miles in the afternoon

4 0
3 years ago
7/9+7/54 what is the answer
kolbaska11 [484]

Answer:

49/54

Step-by-step explanation:

7/9 + 7/54

42/54 + 7/54

49/54

3 0
3 years ago
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