What output does the rule give when the input is (-6,0)?
1 answer:
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11. 8 * 18 = 144 in³, Option D
12. Half the height of 8 cm is 4 cm. Volume = 4 * 6 * 10 = 240 cm³, Option D
13. Double the dimensions you get 8 cm for the height, 6 cm for the radius. Then plug in. V = pi * (6)² * 8 >> pi * 36 * 8 = 288pi or ≈ 904.78, Option C
14. Half of all the dimensions are 1 in, 4 in, and 3 in. 1 * 4 * 3 = 12 in³, Option B
15.
>> 16x = 180 >> x = 11.25 so Option B
16. Option D, 10 cm.
17. Option C, 8.5 in
18. Option B. 10.2 km
19. Option D. 0.82
20. cos 30 = b / 11.5 >> b = 11.5(cos (30)) = 9.96 m, Option C.
12. Half the height of 8 cm is 4 cm. Volume = 4 * 6 * 10 = 240 cm³, Option D
13. Double the dimensions you get 8 cm for the height, 6 cm for the radius. Then plug in. V = pi * (6)² * 8 >> pi * 36 * 8 = 288pi or ≈ 904.78, Option C
14. Half of all the dimensions are 1 in, 4 in, and 3 in. 1 * 4 * 3 = 12 in³, Option B
15.
16. Option D, 10 cm.
17. Option C, 8.5 in
18. Option B. 10.2 km
19. Option D. 0.82
20. cos 30 = b / 11.5 >> b = 11.5(cos (30)) = 9.96 m, Option C.
Answer:
It took 1.2 hours to get to the store
Step-by-step explanation:
Let the time taken to reach the store be t₁
Let the time taken to come back be t₂
Let the speed to and from store = s₁ and s₂ respectively
let the distance to the store = d
To the store:
Back from the store:
We are told that total time (t₁ + t₂) = 2 hours
t₁ + t₂ = eqn (1) + eqn (2)
∴ length of trip to the store = t₁
from eqn (1)