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IgorC [24]
3 years ago
5

Which point is the midpoint of segment AB?

Mathematics
1 answer:
Allushta [10]3 years ago
7 0
Point X is the midpoint
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15 of the 25 students Brought their own lunch. What percent of the students brought their own lunch?
bagirrra123 [75]

Answer:

60%

Step-by-step explanation:

1: 15 divided by 25 to get 0.6

2: multiple 0.6 by 100 to get 60%

5 0
3 years ago
Select the equation that most accurately depicts the word problem. Jim weighs 30 pounds less than Tom, and together they weigh 2
Amiraneli [1.4K]
 <span>n=toms weight 

(n-30)=jims weight 

and together they weigh 210 

so it would be (n - 30) + n = 210</span><span>
</span>
4 0
3 years ago
At the first pep rally of the season, the football team and the volleyball team were presented to the student body. During the p
Darina [25.2K]

Answer:

A. f + y ≤ 11

17f + 287 ≤ 242

Step-by-step explanation:

[] Let <em>f</em> be football players and <em>v</em> be volleyball players.

-> The total time must be less than or equal to 242 seconds.

-> If football players talked for 17 seconds, we can write it as 17f.

-> If volleyball players talked for 28 seconds, we can write it as 28v.

[] Coming back to the first point I made, the total time must be less than or equal to 242 seconds.

-> 17f + 28v ≤ 242

[] This is going to be a part of our system of inequalities

-> Because of this, we rule out the following options.

B & D - the football players talk for 17 seconds, not the volleyball players

C ​ - not less than or equal too, only less than

[] This leaves us with the option of A.

-> The first part of it also works. If 11 players can talk to the crowd, then the total of f and v must be equal too or less than 11.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

5 0
2 years ago
–5x+8y= 10<br> 7x-2y= -14
Lostsunrise [7]

Answer:

x=2,y=0

(You did not provide enough information for me to know what to do with said equations, so I'm assuming it was System of Equations.)

7 0
3 years ago
consider the following scenario: Assume daily protein intake values in a population of athletes are known to have a standard dev
Kipish [7]

Answer:

The 95% confidence interval for the population mean daily protein intake is between 69.97g and 84.03g.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96*\frac{58.6}{\sqrt{267}} = 7.03

The lower end of the interval is the sample mean subtracted by M. So it is 77 - 7.03 = 69.97g.

The upper end of the interval is the sample mean added to M. So it is 77 + 7.03 = 84.03g.

The 95% confidence interval for the population mean daily protein intake is between 69.97g and 84.03g.

5 0
3 years ago
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