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tester [92]
3 years ago
5

A 21-foot tree casts a 38-foot shadow directly down a slope when the angle of elevation of the sun is 32 degrees. Find theta, th

e angle of elevation of the ground (to the nearest tenth of a degree)
Mathematics
2 answers:
Ulleksa [173]3 years ago
6 0

Answer: 35 degree.

Step-by-step explanation:

The angle of elevation makes the height of the tree as opposite, while the shadow it casts is the hypotenuse.

Using trigonometry

[email protected] = opposite/hypotenuse

[email protected] = 21/38

[email protected] = 0.55

@ = sin^0.55

@ = 33.54

@ = 35 degree, to the nearest tenth degree.

ANEK [815]3 years ago
3 0

Answer:

3.97°

Step-by-step explanation:

Let

θ = desired angle

α =32° - θ = the angle above ground to the top of the slope

θ = 32° - a

If angle of the sun is 32° above a level horizon, then the angle at the top of the slope is given as δ = 90 - 32 = 58°. Now we can measure a

38/sin(58°) = 21/sin a

sin a = [21 sin(58°)]/38

Sin a = 0.47

a = arcsin 0.47 = 28.03

Since,

θ = 32° - a

θ = 32° - 28.03° = 3.97°

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Answer:

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Step-by-step explanation:

Look at the circles and what is shaded on the number line.  The first circle is at x=3, and it's an open circle.  An open circle means that the interval does not include that point.  The arrow is going to the left, meaning x < 3.

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When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra
Sergeu [11.5K]

Answer:

r=\sqrt{10}\text{ m}

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

V=\pi r^2h, where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be h = 0.7 meters at V=22\text{ m}^3.

Upon substituting these values in above formula, we will get:

22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})

22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}

\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2

r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}

r^2=10\text{ m}^2

Now, we will take positive square root of both sides as radius cannot be negative.

\sqrt{r^2}=\sqrt{10\text{ m}^2}

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Answer:

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