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2 years ago

What is the slope of the line through (-1, 2) and (-3,-2)?

Mathematics

1 answer:

Burka [1]2 years ago

8 0

The answer of the slope or Gradient of the line is 2

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Can you help me Solve this and show the stepd

NikAS [45]

130-51 is 79 this is it D

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3 years ago

What are the factors of x^2 + 3x -4 ?

algol13

Answer:

1 and -4

Step-by-step explanation:

cause when you factor the equation its (x-1)(x+4)

4 0

3 years ago

Read 2 more answers

Given the original number n. Multiply the number by 9. Add 99. Divide this sum by 9. Subtract the original number, n, from the q

tangare [24]

Answer:

Step-by-step explanation:

Hello,

Given the original number n.

$\large \boxed{n}$

Multiply the number by 9.

$\large \boxed{9n}$

Add 99.

$\large \boxed{9n+99}$

Divide this sum by 9.

$\large \boxed{\dfrac{9n+99}{9}=n+11}$

Subtract the original number, n, from the quotient.

$\large \boxed{n+11-n=11}$

Thank you.

4 0

2 years ago

TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?

egoroff_w [7]

Answer:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

Step-by-step explanation:

$3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12$

Taking square root both sides, we get

$\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}$

Therefore, the values of $b$ are:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

5 0

3 years ago

Read 2 more answers

Pls help<br> will mark brainliest

yanalaym [24]

Answer:

1.93433

Step-by-step explanation:

Since all triangles have an interior angle sum of 180, the second angle is 45. this also means that x and y are equal. Using the pythagorean theorem, we can produce the equation $2\sqrt{14} = 2x^2$ . dividing both sides by two we get $x^2= \sqrt{14}$ . when we take the square root of root 14 we get 1.934335

4 0

2 years ago