First one is the correct one, because it is asked for a sum of 1 and 6, which is (1+6), and then all of that divided by 7 => (1+6)/7
Answer:
0.81
Step-by-step explanation:
<span>Give that </span>t<span>he frequency of G5 is 783.99 Hz.
To find the frequency of the note that is a perfect fifth above G5, we recall that </span>the frequencies of notes that are a 'perfect'
fifth apart are in the ratio of 1.5
i.e. <span>the frequency of the note that is a perfect fifth above G5 divided by </span><span>t<span>he frequency of G5 equal 1.5
Let the </span></span><span><span>frequency of the note that is a perfect fifth above G5 be F, then
F / </span>783.99 = 1.5
F = 1.5 x 783.99 = 1175.99
Therefore, </span>the <span>frequency of the note that is a perfect fifth above G5</span> is 1175.99 Hz
Answer:
b = 25m
Step-by-step explanation:
Hi there!
We're given angle B and the length of <em>a</em> in this right triangle. We must solve for the length of <em>b</em>. <em>a</em> and <em>b</em> are the two legs of the right triangle.
In this case, we can use the tangent ratio:
Plug in the given information:
Therefore, b = 25m.
We can also use this using special triangle rules. 
radians is equal to 45 degrees, making this a 45-90-45 triangle. This would make <em>a</em> and <em>b</em> equal in length.
I hope this helps!
Answer:
Ix - 950°C I ≤ 250°C
Step-by-step explanation:
We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.
And that this temperature is x.
This means that the minimum value of x is 700°C while maximum of x is 1200 °C
Let's find the average of the two temperature limits given:
x_avg = (700 + 1200)/2 =
x_avg = 1900/2
x_avg = 950 °C
Now let's find the distance between the average and either maximum or minimum.
d_avg = (1200 - 700)/2
d_avg = 500/2
d_avg = 250°C.
Now absolute value equation will be in the form of;
Ix - x_avgI ≤ d_avg
Thus;
Ix - 950°C I ≤ 250°C
