They have to have good vision
Eliminate x's by adding te 2 equations
add them
-2x+15y=24
<u>2x+9y=24 +</u>
0x+24y=48
24y=48
divide both sides by 24
y=2
sub back
2x+9y=24
2x+9(2)=24
2x+18=24
minus 18 both sides
2x=6
divide 2
x=3
x=3
y=2
(x,y)
(3,2)
Answer: NONE
<u>Step-by-step explanation:</u>
Consider that m is the degree of the numerator and n is the degree of the denominator.
The rules for horizontal asymptote (H.A.) are as follows:
If m > n then no H.A. (use long division to find the slant asymptote)
If m = n then H.A. is y = leading coefficient of numerator/leading coefficient of denominator
If m < n then H.A. is y = 0
Given: g(x) = 5x⁵/(x³ - 2x + 1)
--> m = 5, n = 3
Since m > n then there is no H.A.
![384=2^7\cdot3=2^6\cdot2\cdot3=(2^2)^3\cdot6=4^3\cdot6\\\\ \sqrt[3]{384}=\\ \sqrt[3]{4^3\cdot6}=\\ \sqrt[3]{4^3}\cdot\sqrt[3]{6}=\\ 4\sqrt[3]6\Rightarrow C](https://tex.z-dn.net/?f=384%3D2%5E7%5Ccdot3%3D2%5E6%5Ccdot2%5Ccdot3%3D%282%5E2%29%5E3%5Ccdot6%3D4%5E3%5Ccdot6%5C%5C%5C%5C%0A%5Csqrt%5B3%5D%7B384%7D%3D%5C%5C%0A%5Csqrt%5B3%5D%7B4%5E3%5Ccdot6%7D%3D%5C%5C%0A%5Csqrt%5B3%5D%7B4%5E3%7D%5Ccdot%5Csqrt%5B3%5D%7B6%7D%3D%5C%5C%0A4%5Csqrt%5B3%5D6%5CRightarrow%20C)
