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3 years ago

What is 9/16 x 12/13 and 7/10 x 5/28

Mathematics

2 answers:

lilavasa [31]3 years ago

8 0

Answer:

1. 9/16 * 12/13 = 27/52

2. 7/10 * 5/28 = 1/8

Step-by-step explanation:

9 / 16 * 12/13

9 * 12 = 108

16 * 13 = 208

108 / 208

Simplify:

27/52

7 / 10 * 5 / 28

7 * 5 = 35

10 * 28 = 280

Simplify:

1/8

Snowcat [4.5K]3 years ago

3 0

Answer:

27/52 and 1/8

Step-by-step explanation:

First step is to multiply the numerators and denominators together.

9/16 x 12/13 = (9 x 12)/(16 x 13)=

108/208

Simplify by dividing by 4. (Greatest common factor)

27/52

-------------------------------------------------------------------------------------------------

multiply the numerators and denominators together.

7/10 x 5/28 = (7 x 5)/ (10 x 28)

35/280

Simplify by dividing by 35. (Greatest common factor)

1/8

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One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)