Answer:
A third type of circuit involves the dual use of series and parallel connections in a circuit; such circuits are referred to as compound circuits or combination
Explanation:
Answer:
0.196 M
Explanation:
First, we have to calculate the moles of sodium hydroxide.
moles = mass / molar mass
moles = 3.9280 g / (39.997 g/mol) = 0.098207 mol
It is important to realize that even though 300 mL is the volume of water firstly added to dissolve the hydroxide, the flask is then filled to the mark, meaning that the volume of the solution is 500 mL = 0.500 L.
The molar concentration of sodium hydroxide is:
The concentration is an intensive property, that is, it does not depend on the amount of matter. As a consequence, the concentration of the 50 mL of solution in the buret is the same as the concentration in the flask.
Answer:
Check explanation
Explanation:
Before delving into the question, let us check some facts about buffer solution.
What is a buffer solution? : A buffer solution is a solution that has resistance towards the change in pH upon the addition of strong base or strong acid. The reaction below shows how buffer solution react with small addition of strong base and Strong acids;
HA + OH^- ------------------> A^- + H2O.------------(1).
In the equation (1) above the conjugate acid react with the base and neutralized it.
A^- + H^+ ------------------------------> HA.---------------------(2)...
In the equation (2) above, the conjugate base react with the acid and neutralized it.
Hence, the chemical reaction occuring as NaOH and HCl are buffered by sodium dihydrogen Phosphate and sodium hydrogen Phosphate are there below;
(1). Upon the addition of strong base:
H2PO4^- + OH^- ---------> HPO4^2- +
H2O.
(2). Upon the addition of strong acid:
HPO4^2- + H3O^+ ----------> H2PO4^2- + H2O.
The answer would be D.
Hope this helps!! (: