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leonid [27]
2 years ago
7

To get more electric current , we have to connect them in ______ combination.​

Chemistry
1 answer:
Sever21 [200]2 years ago
3 0

Answer:

A third type of circuit involves the dual use of series and parallel connections in a circuit; such circuits are referred to as compound circuits or combination

Explanation:

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What is the ROUNDED atomic number for this elements?
denis-greek [22]
Sodium/Atomic number

11

Gold/Atomic number

79
Potassium/Atomic number

19

Silicon/Atomic number

14




8 0
3 years ago
Coffee is decaffeinated industrially using supercritical (sc) CO2. One advantage to using scCO2 is that the polarity of the supe
koban [17]

Answer:

Yes

Explanation:

A supercritical fluid has good properties for both liquid and as for extraction properties, the advantages then include:

  • The fact that it has a lower viscosity than liquid CO2 allowing it to move through and around coffee beans more thoroughly with creating back pressure
  • Its density is comparable to that of liquid CO2 meaning there is much CO2 per litre as there is liquid form making it more efficient
  • It has a higher diffusivity than liquid CO2 which aids with penetration of the coffee beans on a molecular level

This experiment would not work with tea leaves because they also contain caffeine

6 0
3 years ago
Write an equation between the carbonate and the acid​
allochka39001 [22]

Answer:

In general an acid reacts with a carbonate or hydrogen-carbonate to produce a salt, carbon dioxide gas and water.

8 0
2 years ago
What is The cellular process that releases the energy stored in food molecules
notka56 [123]

Respiration. That is the process.

7 0
3 years ago
The pOH of an aqueous solution at 25°C was found to be 1.20. The pH of this solution is . The hydronium ion concentration is M.
frosja888 [35]

Answer:

pH = 12.80

[H3O+] = 1.58 * 10^-13 M

[OH-] = 0.063 M

Explanation:

Step 1: Data given

pOH = 1.20

Temperature = 25.0 °C

Step 2: Calulate pH

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 1.20 = 12.80

Step 3: Calculate hydronium ion concentration

pH = -log[H+] = -log[H3O+]

12.80 = -log[H3O+]

10^-12.80 = [H3O+] = 1.58 * 10^-13 M

Step 4: Calculate the hydroxide ion concentration

pOH = 1.20 = -log [OH-]

10^-1.20 = [OH-] = 0.063M

Step 5: Control [H3O+] and [OH-]

[H3O+]*[OH-] = 1* 10^-14

1.58 *10^-13 * 0.063 = 1* 10^-14

5 0
3 years ago
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