For the rocket engine a lean or excessively rich air-fuel ratio will lead to a compromise in the power output and ultimately the altitude the rocket will reach. Hence which ever the ratio the altitude is greatly affected, unless the ideal ratio is archived.
The air-fuel ratio is the ratio of the amount of air need to burn a part of fuel in a combustion cycle, the ratio is basically a compromise between fuel economy and optimum power output.
For a gasoline engine for example, the ideal air-fuel mixture of 14.7 parts air to 1 part fuel.
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Answer:
2.28 atm
Explanation:
V₁ = 2.33L, V₂ = 1.08L
T₁ = 289K, T₂ = 304K
P₁ = 1.05 atm, P₂ = ?
Where V₁ and V₂ are initial and final volume respectively
T₁ and T₂ are initial and final temperature respectively
P₁ and P₂ are initial and final pressure respectively
The formula to be used here is the general gas equation:
P₁V₁/T₁=P₂V₂/T₂
1.05 × 2.23/289 = P₂ × 1.08/304
P₂ × 1.08 × 289 = 1.05 × 2.23 × 304
P₂ = (1.05 × 2.23 ×304) ÷ (1.08 × 289)
P₂ = 711.82 ÷ 312.12
P₂ = 2.28 atm
Because <span>Gold is a very inert metal, and won't really react with oxygen in the air.
The only reason other metals tarnish, such as copper, silver, steel/iron, is
because they're freely reacting with air, to produce a metal oxide surface layer. </span>
Answer:First calculate the moles of selenium by multiplying the mass x molar mass 90.2 × 78.96 = 7122.2 moles. Number of moles multiplied by ...
Explanation: