Answer:
P = 0,0012 or P = 0.12 %
Step-by-step explanation:
We know for normal distribution that:
μ ± σ in that range we find 68.3 % of all values
μ ± 2σ ⇒ 95.5 % and
μ ± 3σ ⇒ 99.7 %
Fom problem statement
We have to find (approximately) % of cars that reamain in service between 71 and 83 months
65 + 6 = 71 ( μ + σ ) therefore 95.5 % of values are from 59 and up to 71 then by symmetry 95.5/2 = 49.75 of values will be above mean
Probability between 65 and 71 is 49.75 %
On the other hand 74 is a value for mean plus 1, 5 σ and
74 is the value limit for mean plus 1,5 σ and correspond to 49,85 (from z=0 or mean 65).
Then the pobabilty for 83 have to be bigger than 49.85 and smaller than 0,5 assume is 49.87
Finally the probability approximately for cars that remain in service between 71 and 83 months is : 0,4987 - 0.49.75
P = 0,0012 or P = 0.12 %
Answer:
Prakash is a pilot change into yes no question
Answer:
300 phones the company activated in one minute
As per unitary method, calculation been done to find the value of single unit from the value of multiple units.
So, she is dividing the total number of phone activated by number of minutes taken to activate to find phone activate in one minute.
Step-by-step explanation:
Here is the correct question: Meg wants to find how many phones the company activated in one minute. Explain why meg can use 15000 divided by 50 to find the answer.
As per unitary method, calculation been done to find the value of single unit from the value of multiple units.
Therefore, in the above question Meg knew the number of total phone activated by company in 50 minutes, which is 15000.
Now, she want to find how many phones the company activates in one minute.
So, she is dividing the total number of phone activated by number of minutes taken to activate to find phone activate in one minute.
Phones the company activated in one minute= 
∴ 300 phones the company activated in one minute.
Answer:

Step-by-step explanation:
convert 1 3/4 into improper fraction: 7/4
we got this from 4 × 1 = 4, then 4 + 3 = 7
the denominator stays the same
we need to subtract the amount that he has left from
the total amount:
make the number 3 have the same denominator as 7/4

convert 5/4 into a mixed number:
the numerator has to be the same, so how many lots of 4 can go into 5 without a remainder? it is 1
4 × 1 = 4
1 is left over, so the numerator is 1
4 + 1 = 5
