The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
x = 25
Step-by-step explanation:
120 = 70 + 2x
120 - 70 = (70 - 70) + 2x
50 = 2x
50/2 = 2x/2
x = 25
Answer:
It's choice 2. c = 3 sin 45 / sin 40.
Step by-step explanation:
m< A = 180 - 45-95
= 180 - 140
= 40 degrees.
So by the Sine Rule:
c / sin 45 = 3 / sin A
Cross multiply:
c sin A = 3 sin 45
c = 3 sin 45 / sin 40.
-5 because it is closest to zero and -17 is farther than zero on a number line :) <span />
Answer:
C) As the amount of snow increases, the number of accidents increases.
Step-by-step explanation:
An image showing the scatter plot is attached.
From the attached imaged, the scatter plot is a straight line which goes up along the X - Y axis.
X = snowfall
Y = accident
Since the scatter plot is going up increasingly for any value plotted; it means as the amount of snow increases, the number of accidents increases. That is, as X (snowfall) increases Y (accident) increases also.
