The numbers are 105 and 50
<em><u>Solution:</u></em>
Let "x" be the first number
Let "y' be the second number
Twice a number plus twice a second number is 310
Therefore,
twice of x + twice of y = 310
2x + 2y = 310 ---------- eqn 1
The difference between the numbers is 55
x - y = 55 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
x = 55 + y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
2(55 + y) + 2y = 310
110 + 2y + 2y = 310
4y = 310 - 110
4y = 200
<h3>y = 50</h3>
<em><u>Substitute y = 50 in eqn 3</u></em>
x = 55 + 50
<h3>x = 105</h3>
Thus the numbers are 105 and 50
Answer:
It is the same speed everyday
Step-by-step explanation:
It is a constant speed
Answer:
12 and 13
Step-by-step explanation:
(a)
To evaluate f(g(2)), evaluate g(2) then use the value obtained to evaluate f(x)
g(2) = 2(2) - 1 = 4 - 1 = 3, then
f(3) = 3² + 3 = 9 + 3 = 12
--------------------------------------------
(b)
To evaluate g(f(2)), evaluate f(2) the use the value obtained to evaluate g(x)
f(2) = 2² + 3 = 4 + 3 = 7, then
g(7) = 2(7) - 1 = 14 - 1 = 13
