Answer:
my uncle just turned 39 and I am 13 which is supposed to be x so...
x3=39
Step-by-step explanation:
in other words: 13 times 3 is 39
If correct, will you please mark me brainliest?
 
        
             
        
        
        
<h2>Answer</h2>
C.) 1
<h2>Explanation </h2>
Remember the rules for shifting functions: 
 shifts the function b units upward
 shifts the function b units upward
 shifts the function b units downward
 shifts the function b units downward
 shifts the function b units to the left
 shifts the function b units to the left
 shifts the function b units to the right
 shifts the function b units to the right
Since we want tho shift  5 units to the right, we are using the rule:
 5 units to the right, we are using the rule:  shifts the function b units to the right; in other words, we need to subtract 5 units to the input of the function:
 shifts the function b units to the right; in other words, we need to subtract 5 units to the input of the function: 


But notice that there is already a negative sign in  , so to get
, so to get  , k must be equal to positive 1.
, k must be equal to positive 1.
 
        
        
        
we are given

To find x-intercept means we have to find zeros 
and for finding zeros , we will use quadratic formula 
and we have it has two x-intercepts 
so, it's discriminant must be greater than 0
so, we will find discriminant

now, we can compare with 


and then we can find a , b and c

now, we can find D


It has two x-intercepts 
so, 

now, we can solve for m 


 ............Answer
............Answer
 
        
                    
             
        
        
        
Answer:
x = 0, -4 and -3.
Step-by-step explanation:
The given expression is "3x to the power of 3 + 21x squared + 36x = 0".
We can write this expression as follows :

Taking 3x common.

x = 3

Hence, the solution of the given quadratic equation are x = 0, -4 and -3.
 
        
             
        
        
        
Let 2x – y = 3 ——— equation 1
Let x + 5y = 14 ——— equation 2
Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3
• Put eqn 3 in eqn 2
(y + 3 / 2) + 5y = 14
6y = 14 – 3/2
6y = 25/2
y = 25/12
• put y = 25/12 in eqn 3
x = (25/12 + 3/2) 
x = 43/12