Answer: the probability of a student being overdrawn by more than $18.75 is 0.674
Step-by-step explanation:
Since the bank overdrafts of ASU student accounts are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = bank overdraft of Asu students.
µ = mean
σ = standard deviation
From the information given,
µ = $21.22
σ = $5.49
We want to find the probability of a student being overdrawn by more than $18.75. It is expressed as
P(x > 18.75) = 1 - P(x ≤ 18.75)
For x = 18.75,
z = (18.75 - 21.22)/5.49 = - 0.45
Looking at the normal distribution table, the probability corresponding to the z score is 0.326
Therefore,
P(x > 18.75) = 1 - 0.326 = 0.674
Answer:
67 years old. (you only gave 4 people and missed out one person)
Step-by-step explanation:
take all the ages first and put the unknown (age of the person who entered the room) as x.
14, 16, 16, 13, x
all of these numbers added to together would be:
59 + x
Because the question is talking about the mean age, to find mean:
add all the values in the data (ages) and divide by the total number of values on the list. (in your case would be 6 people (following your question) but you gave only 5 people including the x).
then (59 + x) / 6 = 21
21 x 6 = 126
126 = 59 + x
x = 67
Answer:
23
Step-by-step explanation:
1/2 times 10=5
5-2=3
3+(2 times 10)=23
Answer:
Step-by-step explanation:
yes
Answer:
1,2,3 and then the last two
Step-by-step explanation:
