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3 years ago

There are 50 bees in a hive. Some bees fly out. If fewer than 20 bees are still in the hive, how many bees could have flown out?

Mathematics

2 answers:

Deffense [45]3 years ago

4 0

Answer:

30 bee maybe i'm not sure

Step-by-step explanation:

good luck tho.

ycow [4]3 years ago

4 0

Answer:

30 bees

Step-by-step explanation:

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Generate an equivalent expression using prime factorization for

KiRa [710]

3 , 20 , 2 , 6 ,10 , 5

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3 years ago

Y=2X-1 5x-4y=1 is (1,1) a solution of the system

Natasha2012 [34]

You are given the system of equations

$\left\{\begin{array}{l}y=2x-1\\5x-4y=1.\end{array}\right.$

If you want simply to know whether (1,1) is a solution of this system, then substitute x=1 and y=1 into both equations:

$\left\{\begin{array}{l}1=2\cdot 1-1\\5\cdot 1-4\cdot 1=1\end{array}\Rightarrow \begin{array}{l}1=1\\1=1\end{array}\right.$

This means that (1,1) is a solution, because both iqualities hold.

6 0

3 years ago

Jake is going to multiply the number 10 by a fraction. Which of the following will be true about the product?

nikdorinn [45]

Answer:

Answer will be less than 10

Step-by-step explanation:

8 0

3 years ago

The city of Madison regularly checks the quality of water at swimming beaches located on area lakes. Fifteen times the concentra

Maksim231197 [3]

Answer:

The sample standard deviation is 393.99

Step-by-step explanation:

The standard deviation of a sample can be calculated using the following formula:

$s=\sqrt[ ]{\frac{1}{N-1} \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }$

Where:

$s=$ Sample standart deviation

$N=$ Number of observations in the sample

${\displaystyle \textstyle {\bar {x}}}=$ Mean value of the sample

and $\sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }$ simbolizes the addition of the square of the difference between each observation and the mean value of the sample.

Let's start calculating the mean value:

$\bar {x}=\frac{1}{N} \sum_{i=1}^{N}x_{i}$

$\bar {x}=\frac{1}{15}*(180+1600+90+140+50+260+400+90+380+110+10+60+20+340+80)$

$\bar {x}=\frac{1}{15}*(3810)$

$\bar {x}=254$

Now, let's calculate the summation:

$\sum_{i=1}^{N}(x_{i}-\bar {x}) ^{2} }=(180-254)^2+(1600-254)^2+(90-254)^2+...+(80-254)^2$

$\sum_{i=1}^{N}(x_{i}-\bar {x}) ^{2} }=2173160$

So, now we can calculate the standart deviation:

$s=\sqrt[ ]{\frac{1}{N-1} \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }$

$s=\sqrt[ ]{\frac{1}{15-1}*(2173160)}$

$s=\sqrt[ ]{\frac{2173160}{14}}$

$s=393.99$

The sample standard deviation is 393.99

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4 years ago

The front side of a barn is shown in this scale drawing.the width of the barn in the picture is 4 in the scale that maps the dra

Korolek [52]

Answer:

Step-by-step explanation: internet is a answer

6 0

3 years ago

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