P=focal legnth is the distance from the focus to the vertex, which also is the disance from the directix to the vertex
therefor
distance from directix to focus=2 times focal legnth
find distance
horizontal distance
from y=-0.6 to y=2.6, that is distance ot 3 units
3/2=1.5
focal distance=1.5
Answer:
Find out the what is the slope of the line that passes through the points (-3, 5) and (1, 7) .
To prove
Formula for slope
![m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By_%7B2%7D%20-%20y_%7B1%7D%7D%7Bx_%7B2%7D%20-%20x_%7B1%7D%7D)
The points are (-3, 5) and (1, 7) .
Put in the formula
![m = \frac{7 - 5}{1 - (-3)}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B7%20-%205%7D%7B1%20-%20%28-3%29%7D)
![m = \frac{2}{1 + 3}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B2%7D%7B1%20%2B%203%7D)
![m = \frac{2}{4}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B2%7D%7B4%7D)
Simplify the above
![m = \frac{1}{2}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
Option (A) is correct .
Answer:
Step-by-step explanation:
Distribute the 2
y + 7 = 2x + 10
Subtract 7 on both sides
y = 2x +3