Find the greatest common factor of 15/40

34. Lora is thinking of a number. It is less than 50 It is a 2-digit number. 3 is a factor of this number. The sum of its digits

-Dominant- [34]

Answer:

B

Step-by-step explanation:

The number is between 10 and 49

The number is divisible by 3

Let the 10s digit = x

Let the units digit = y

1/3 * (10x + y) = x + y multiply both sides by 3

10x + y = 3(x +y) remove the brackets.

10x +y = 3x + 3y Subtract 3x from both sides

10x - 3x + y = 3y Combine\

7x + y = 3y Subtract y from both sides.

7x = 3y - y Combine

7x = 2y

x can't be very big. Even taking 1/3 will get out of range is you use 6.

Also x should be an even number. The units digit cannot have a fraction in it.

Try making x = 2

7*2 = 2*y

14 = 2y Divide by 2

14/2 = y

y = 7

So the number is possibly 27. Let's check it out.

The number is between and includes 10 and 49. 27 is between these two endpoints.
27 is divisible by 3
1/3(27) = sum of digits
9 = (2 + 7)

All of the conditions are met. It's B

8 0

2 years ago

Solve: 3x-5/2 +x+ 2x-3/3 = 5/6 - 3x/2

Vlad [161]

Answer:

x = 26/45

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

0.98x0.23 what is 0.98 times 0.23?

fomenos

Answer:

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Step-by-step explanation:

3 0

2 years ago

A microwave is placed on top of a stand. The stand is 3 feet 9 inches tall, and the microwave is 3 feet 11 inches tall. Together

Ivanshal [37]

3+3= 6ft
11+9= 20 inches
20-12= 8
So 7ft 8 inches tall together

8 0

3 years ago

Solve for x and y it says i need 20 characters so i’m writing more

fgiga [73]

Answer:

 For y :

From pythogras theorem:

${ \tt{ {(hypotenuse)}^{2} = {(adjacent)}^{2} + {(opposite)}^{2} }} \\ { \tt{ {(7 + 3)}^{2} = \{( {x}^{2} + 9) \} {}^{2} + {y}^{2} }} \\ { \tt{100 = ( {x}^{4} + 18 {x}^{2} + 81) + {y}^{2} }} \\ { \tt{ {y}^{2} = 100 - {x}^{4} - {18x}^{2} - 81 - - - - (a) }}$

For the second largest inner triangle;

${ \tt{ {y}^{2} = {7}^{2} + {x}^{2} }} \\ { \tt{ {y}^{2} - = 49 + {x}^{2} - - - - (b) }}$

Equate (a) and (b):

${ \tt{100 - {x}^{4} - 18 {x}^{2} - 81 = 49 + {x}^{2} }} \\ { \tt{100 - 49 - 81 = {x}^{4} + 19 {x}^{2} }} \\ { \tt{ - 30 = {x}^{2}( {x}^{2} + 19x)}} \\ { \boxed{ \tt{for \: \: {x}^{2} = - 30...imaginary \: value }}} \\ {\boxed{ \tt{for \: \: ( {x}^{2} + 19x ) \: = - 30}}} \\ { \tt{ {x}^{2} + 19x + 30 = 0 }} \\ { \tt{}}$

solve the equation to get values of x, which will give you y

7 0

1 year ago