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emmainna [20.7K]
3 years ago
8

Simplify each expression as much as possible, and rationalize denominators when applicable. √(17/25)=?

Mathematics
1 answer:
amm18123 years ago
7 0

Answer:

The answer to your question is:  \frac{\sqrt{17}}{5}

Step-by-step explanation:

\sqrt{\frac{17}{25} }  = \frac{\sqrt{17} }{\sqrt{25}}  = \frac{\sqrt{17}}{5}

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Fred's frog jumped 7 times as far as Al's frog. The two frogs jumped a total of 56 inches. How far did Fred's frog jump?
sergey [27]

8 inches

Divide 56 by 7 which equals 8 so Fred's frog jumped 8 inches.

5 0
3 years ago
5. A solid has a circle of radius r as its base. All sections of the solid perpendicular to the diameter along the x-axis are is
AleksandrR [38]

Answer:

 \frac{16r^3}{3}

Step-by-step explanation:

In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).

\int\limits^r_a {2(x^2+r^2 )} \, dx

The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.

Evaluating the integral gives use that it is equal to;

\frac{16r^3}{3}

Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.

If you found this answer helpful please consider leaving 5 stars, giving it a like, or if you asked this question, mark this answer as Brainliest. Thanks!

4 0
2 years ago
What is 15% of 60 show your work to prove your answer
Mila [183]
<span>To convert a percentage to a decimal you move the decimal two places to the left. Therefore:

15.% becomes .15

You then multiply this decimal to the number you are trying to find the percentage of.

.15 × 60 = 9.

9 is 15% of 60.
</span>
3 0
3 years ago
Read 2 more answers
(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)
laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

(D) Example of a nonlinear fourth order ODE:

K^4(x) - \beta f [x, k(x)] = 0

4 0
3 years ago
Solve the system of equations graphicallySolution=?
BigorU [14]

The given system is

\begin{cases}y=\frac{5}{2}x-8 \\ y=-\frac{1}{2}x-2\end{cases}

Given that y = y, let's combine the equations

\frac{5}{2}x-8=-\frac{1}{2}x-2

Let's solve for x

\begin{gathered} \frac{5}{2}x+\frac{1}{2}x=8-2 \\ \frac{6}{2}x=6 \\ 3x=6 \\ x=\frac{6}{3} \\ x=2 \end{gathered}

Then, we find y

y=-\frac{1}{2}x-2=-\frac{1}{2}\cdot2-2=-1-2=-3

The solution is (2, -3).

The image below shows the solution graphically.

3 0
1 year ago
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