Answer:
Option C,
Step-by-step explanation:
Answer: Option C,
Answer:
a)
b)
c)
Step-by-step explanation:
Part a
The significance level given is and the degrees of freedom are given by:
Since we are conducting a right tailed test we need to find a critical value on the t distirbution who accumulates 0.1 of the area in the right and we got:
Part b
The significance level given is and the degrees of freedom are given by:
Since we are conducting a left tailed test we need to find a critical value on the t distirbution who accumulates 0.01 of the area in the left and we got:
Part c
The significance level given is and and the degrees of freedom are given by:
Since we are conducting a two tailed test we need to find a critical value on the t distirbution who accumulates 0.025 of the area on each tail and we got:
Answer:
B cuz both can be divided by 7
Given:
The given equation is:
Where x is the number of tickets sold for the school play a y is the amount of money collected for the tickets.
To find:
The correct table of values from the given options.
Solution:
We know that the number of tickets and amount of money collected for the tickets cannot be negative. So, options A and B are incorrect.
We have,
For ,
For ,
For ,
For ,
In option C, all the ordered pairs (0,0), (10,50), (51,255), (400,2000) are in the table. So, option C is correct.
For
Since the ordered pair (65,350) does not satisfy the given equation, therefore the option D is incorrect.
Hence, the correct option is C.
Total balance in Mr. Copley at the end of the month = $1473.61.
Initial deposite = $75 (not shown in his checkbook).
Let us assume his balance at the beginning of the month = x.
Total balance at the end of the month = The balance at the beginning of the month + total deposite.
$1473.61 = x + 75.
Subtracting 75 from both sides, we get
1473.61 -75 = x + 75 -75.
1398.61 = x.
Therefore, his balance at the beginning of the month was $1398.61.