All categories

3 years ago

Find the prime factorization of the following 2 numbers 36 and 72?

Mathematics

1 answer:

Kryger [21]3 years ago

5 0

Answer:

36 = 2² x 3²

72=2³×3²

Step-by-step explanation:

You might be interested in

Please help, I suck at math

ira [324]

Answer:

Step-by-step explanation:

(-3,1) (5,3)

$slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{3-1}{5-(-3)}\\\\=\frac{2}{5+3}\\\\=\frac{2}{8}\\\\=\frac{1}{4}$

= 0.25

5 0

3 years ago

Add 78, 139, and 14, and then divide by 44.

denpristay [2]

Answer:

5.24, 21/4, or 5 and 1/4

Step-by-step explanation:

78+139+14 = 231

231/44 = 5.25

Or 21/4 (improper fraction)

Or 5 and 1/4 (mixed number)

I'm not exactly sure what you were asking I hope that helps!

8 0

3 years ago

Roxie is picking out some movies to rent, and she is primarily interested in horror films and foreign films. She has narrowed do

olya-2409 [2.1K]

Answer:

2470

Step-by-step explanation:

Roxie must pick 3 movies from 20 horror films and 8 foreign films with at least two horror films.

i) She can pick 2 horror films and 1 foreign film

The number ways this is possible = C(20, 2) * C(8, 1)

$C(20,2)=\frac{20!}{(20-2)!2!}=190\\\\C(7,1)=\frac{7!}{(7-1)!1!}=7$

The number ways this is possible = C(20, 2) * C(8, 1) = 190 * 7 = 1330

ii) She can pick 3 horror films

The number ways this is possible = C(20, 3)

$C(20,3)=\frac{20!}{(20-3)!3!}=1140\\\\$

The number ways this is possible = C(20, 3) = 1140

The number of ways of picking 3 movies from 20 horror films and 8 foreign films with at least two horror films = pick 2 horror films and 1 foreign film + pick 3 horror films

The number of ways of picking 3 movies from 20 horror films and 8 foreign films with at least two horror films = 1330 + 1140 =2470

7 0

3 years ago

What is the greatest common factor of 4k, 18k^4, and 12? a) 2 b) 4 c) 2k d) 4k

Furkat [3]

Answer:

greatest common factor is 2

Step-by-step explanation:

the greatest common factor of 4k, 18k^4, and 12

To find GCf we break the factors of each term and check which factor is common for all the three terms

4k : 2*2*k

18k^4 : 3*3*2*k*k *k*k

12 : 3*2*2

Common factor is : 2

we have only 2 in common for all the three terms

So greatest common factor is 2

5 0

3 years ago

X is a random variable uniformly distributed over

Alexxandr [17]

Answer:

List all of the solutions.

x=(−k,k)=12 the=k=

Step-by-step explanation:

6 0

3 years ago