Question

The area of a rectangle is 65 m2 , and the length of the rectangle is 3 m less than twice the width. find the dimensions of the rectangle.

Answer 1

X = width
2x-3 = length 

$x(2x-3) = 65\\ 2x^2 - 3x - 65 = 0 \\ D=b^2-4ac=(-3)^2-4*2*(-65)=529\\ x_{1,2}= \frac{-bб \sqrt{D} }{2a}= \frac{3б 23}{4} \\ x_1=-5 \ \ \O \\ x_2=6.5$

width = 6.5 m
length  = 2x-3 = 2*6.5 - 3 = 10 m