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kondaur [170]
3 years ago
10

A businessman bought a dealership that is incurring a loss of $500,000 a year. He decided to strategize in order to turn the bus

iness around. In addition to the $500,000 annual loss, his fixed cost for running the dealership on a monthly basis is $5,000. The number of cars sold per week and their probabilities mimic the outcomes of three coins being flipped. The number of cars sold in a week was observed to be the same as the number of tails that appear in a three coin flip. See the distribution:. Number of Tails 0 |1 |2 |3. probablity 1/8 | 3/8 | 3/8 | 1/8
Mathematics
1 answer:
Nikitich [7]3 years ago
5 0

Based from the given data, the expected number of cars sold in one week is B. 1.5.

The equation to solve the problem would be like this. 0*1/8 + 1*3/8 + 2*3/8 + 3*1/8 = 3/2 which when simplified is 1.5.

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Zigmanuir [339]

Answer:

C. t = 10d

Example:

If i rode the bike for 3 miles then

t = 10(3)

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pantera1 [17]

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He rarely turns his back on you.

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Step-by-step explanation:

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3 years ago
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Select the property of equality used to arrive at the conclusion.
artcher [175]

Answer:

A

Step-by-step explanation:

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5 0
3 years ago
Can someone plz help me with this question
Karo-lina-s [1.5K]
Answers are A and E, this is because you can do 3:12 x 4 = 12:48 and 3:12/4 = 1:4 therefore they are all equal values
5 0
4 years ago
What number best completes both equations? 5/7÷1/3=? ?×1/3=5/7
Nat2105 [25]

Consider the given equations:

The first equation is as:

\frac{5}{7} \div \frac{1}{3} = ?

So, \frac{5}{7} \div \frac{1}{3}

= \frac{5}{7} \times \frac{3}{1}

Multiplying the given fractions, we get as

= \frac{15}{7}

Now, consider the second equation as:

? \times \frac{1}{3} = \frac{5}{7}

Multiplying by '3' to both the sides of the equation, we get

? \times \frac{1}{3} \times 3 = 3 \times \frac{5}{7}

? = \frac{15}{7}

So, the number which best completes both the equations is \frac{15}{7}.

6 0
4 years ago
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