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Archy [21]
3 years ago
8

For example #1 what is the solution

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

Answer: what is example 1

Step-by-step explanation: what is it

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- 2 + 0.8) ÷ (- 1.3) =<br><img src="https://tex.z-dn.net/?f=%20%28%20-%202%20%2B%200.8%29%20%5Cdiv%20%28%201%7D%5E%7B2%7D%20%20-
Nookie1986 [14]
(-2 + 0.8) ÷ (1²-1.3) =

(-1.2) ÷ (1-1.3)

(-1.2) ÷ (-0.3)

= 4
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Please help me i really need jt
Dahasolnce [82]

Answer:

Step-by-step explanation:

34

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How to rewrite√-49 -4 in complex number notation
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Sqrt(49)*sqrt (-1) -4 = 7i-4
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Find the sum of the first 50 terms -6, -2, 2, 6,…
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Step-by-step explanation:

3 0
3 years ago
Two planes start flying towards each other simultaneously from two different cities. The distance between the cities is 960 mile
ANTONII [103]

Answer:

257.5 mph

332.5 mph

Step-by-step explanation:

The initial distance between the two planes is 960 miles, while the final distance (after t=1.5 h) is 75 miles, so the total distance covered by the two planes in 1.5h is

d=960-75=885 miles

Calling v1 and v2 the velocities of the two planes, we have the following equations:

(1) v_1 = v_2 + 75 --> velocity of plane 1 exceeds velocity of plane 2 by 75 mph

(2) v_1 t+ v_2 t=885 --> the total distance covered by the two planes is 885 miles (t=1.5 h is the time, and the products v1 t and v2 t represent the distance covered by each plane)

Substituting t=1.5 h, the second equation becomes:

1.5 v_1+1.5 v_2=885\\v_1 + v_2 = 590

By substituting (1) into this last equation, we find:

(v_2+75)+v_2 = 590\\2v_2 + 75 = 590\\2v_2 = 515\\v_2=257.5

And substituting this back into eq.(1), we find

v_1 = 257.5 + 75=332.5

So, the speeds of the two planes are

257.5 mph

332.5 mph



3 0
3 years ago
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