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Naily [24]
4 years ago
8

Multiply and write each product in the form y = ax2 + bx + c. Then identify a, b, and c.

Mathematics
1 answer:
-Dominant- [34]4 years ago
3 0
7) y= x^2-4x
8) y= 2x^2-3x+1
9) y= 9x^2-4
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The floor of a rectangular deck has an area of 600 square feet. The floor is 20 feet wide. How long is the floor? A. 30 ft. B. 2
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<span>A. 30 ft
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4 0
3 years ago
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When p = 12, t = 2, and s = One-sixth, r = 18. If r varies directly with p and inversely with the product of s and t, what is th
bagirrra123 [75]

Answer:

k = \frac{1}{2}

Step-by-step explanation:

Given

p = 12

t = 2

s = \frac{1}{6}

r = 18

r\ \alpha\ p\ * \frac{1}{s * t}

Required

Find the constant of variation

From the question, the variation is as follows

r\ \alpha\ p\ * \frac{1}{s * t}

r\ \alpha\ \frac{p * 1}{s * t}

r\ \alpha\ \frac{p}{s * t}

Convert variation to equation

r\ = k\frac{p}{s * t}

Where k represents the constant of variation

Make k the subject of formula;

Multiply both sides by s * t

r * s * t = k\frac{p}{s * t} * s * t

r * s * t = kp

Divide both sides by p

\frac{r * s * t}{p} = \frac{kp}{p}

\frac{r * s * t}{p} = k

k = \frac{r * s * t}{p}

Substitute the values of p, r, s and t in the above equation

k = \frac{18 * \frac{1}{6} * 2}{12}

k = \frac{6}{12}

Divide numerator and denominator by 6

k = \frac{1}{2}

Hence, the constant of variation is; k = \frac{1}{2}

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3 years ago
Please help!!!!! For the data set shown by the table
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4 years ago
Consider the exponential function f(x)=250(1.03)^x
Leya [2.2K]

Step-by-step explanation:

Exponential function: f(x)=250(1.03)^x

Simplify both sides of the equation.

f(x)=250⋅1.03x

Evaluate the function.

250⋅1.03x

3 0
3 years ago
What is the range of the function y= 3 startroot x+8 endroot?
Illusion [34]

Answer:

First Option

Step-by-step explanation:

When we graph the expression, we should see that an infinite amount of y-values work. Since the domain comprises of all working x-values, we have (negative infinity, positive infinity) or all real numbers as our range, since we have an infinite amount of y-value outputs.

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3 years ago
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