Gotta add a picture to show us what you want us to do.
Answer:
A: 6 triangles with height 10.4 inches each and base 12 inche
B: 62.4 square inches
C: 374.4 square inches
Step-by-step explanation:
Part A: You can form a triangle by connecting E to the top of the segment and connecting the top of the segment to D. Recreating this with each section will create 6 triangles with height 10.4 inches each and base 12 inches.
Part B: The area of a triangle is A = 1/2b*h. Substitute h = 10.4 and b = 12.
A = 1/2*10.4*12 = 62.4
Part C: There are 6 triangles each with area 62.4. So the area of the whole figure will be 6*62.4 = 374.4.
Answer:
d
Step-by-step explanation:
Δ OPG is right with hypotenuse OG being the radius of the circle
Using Pythagoras' identity in the right triangle
OG² = OP² + PG²
[ PG = 11 , since OP is the perpendicular bisector of FG ]
OG² = 8² + 11² = 64 + 121 = 185
Δ OQS is right with hypotenuse OS being the radius
Using Pythagoras' identity
OS² = QS² + OQ² , that is
185 = 13² + x²
185 = 169 + x² ( subtract 169 from both sides )
16 = x² ( take the square root of both sides )
4 = x → d
4 = 2*2
6 = 2*3
9 = 3*3
LCD = 2 * 3* 2 * 3 = 36
so the fractions are 3/4 * 9/9 = 27/36
5/6 = 30/36 and 5/9 = 20/36
3x+4=52
-4 -4
3x=48
divide by 3 on both sides
x=16
