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melisa1 [442]
3 years ago
13

Hello I need help Find the missing side lengths, leave your answers as radicals in simplest form

Mathematics
1 answer:
Jet001 [13]3 years ago
4 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

y =  \frac{1}{2}  \times  \frac{8 \sqrt{3} }{3}  \\

y = \frac{4 \sqrt{3} }{3}  \\

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

x =  \frac{ \sqrt{3} }{2}  \times  \frac{8 \sqrt{3} }{3}  \\

x = \frac{8 \times  { \sqrt{3} }^{2} }{2 \times 3}  \\

x =  \frac{8 \times 3}{2 \times 3}  \\

x =  \frac{8}{2}  \\

x = 4

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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Anastasy [175]

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Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one

<em>For the graph below, what should the domain be so that the function is at least 200?   graph of y equals minus 2 times the square of x plus 30 times x plus 200 </em>

My answer:

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y=-2x^2+30x+200

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y=-2x^2+30x+200 ≥ 200

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Then we get

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