All categories

3 years ago

Hello I need help Find the missing side lengths, leave your answers as radicals in simplest form

Mathematics

1 answer:

Jet001 [13]3 years ago

4 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$y = \frac{1}{2} \times \frac{8 \sqrt{3} }{3} \\$

$y = \frac{4 \sqrt{3} }{3} \\$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$x = \frac{ \sqrt{3} }{2} \times \frac{8 \sqrt{3} }{3} \\$

$x = \frac{8 \times { \sqrt{3} }^{2} }{2 \times 3} \\$

$x = \frac{8 \times 3}{2 \times 3} \\$

$x = \frac{8}{2} \\$

$x = 4$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

You might be interested in

5.6 by the power of negative 5 can someone tell me what that equals PLZ HELP NOW

dmitriy555 [2]

0.00018157659
hope this helps you

8 0

3 years ago

Read 2 more answers

Helpppppppppppppppppppppppppppppppppppppppppppppppppp

valentina_108 [34]

Simplify the radical by breaking the radicand up into a product of known factors.

Exact Form:

√

Decimal Form:

26.94438717

7 0

3 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

Answer:

3003 number of 5-member chess teams can be chosen from 15 interested players.

Step-by-step explanation:

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{360360}{120}$

$15C_5 = 3003$

7 0

3 years ago

Consider a paint-drying situation in which drying time for a test specimen is normally distributed with σ = 7. The hypotheses H0

pshichka [43]

Answer:

(a) The value $\bar x$ = 72.3 is 1.21 standard deviations below the null value of μ.

(b) The mean drying time of paint is not less than 74.

Step-by-step explanation:

The hypothesis for the single mean test is:

H₀: μ = 74 vs. Hₐ: μ < 74.

The information provided is:

σ = 7

n = 25

As the population standard deviation is known, we will use a z-test for single mean.

(a)

The z-score is a Normal distribution with mean 0 and variance 1. It is also defined as the number of standard deviations a raw score is from the mean.

The z-score for sample mean is given by:

$z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}$