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3 years ago

6

What is the value of the rational expression below when x is equal to 4? 12+x/4+x

2 answers:

kozerog [31]3 years ago

8 0

The expression is equal to 2.

Let's take the original equation and put 4 in for every x that we see.

<span>12+x/4+x
12 + (4)/ 4 + (4)
16/8
2</span>

11Alexandr11 [23.1K]3 years ago

6 0

This is easy what you should do is plug in 4 for the x's in the rational expression and what it should look like when finished is: 12+4/4+4.
To remember the steps in which and equation should be solved is:
P=Parentheses
E=Exponents
M=Multiply
D=Division
A=Add
S=Subtract

So the answer to the equation is: 17
Hoped this helped you into solving more equations like this one. :)

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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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2 years ago

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Answer ASAP, please..

Phantasy [73]

Answer:

g(x) = $(x-3)^{2} -4$

Step-by-step explanation:

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6 0

2 years ago

T+2/3t-1/3 I really need this question to be answered

Murrr4er [49]

<u> Equation:</u>

x(x - 5) + 3(x + 5)

<u>Steps:</u>

x(x - 5) + 3(x + 5)

<u>Expand:</u>

x(x - 5 ): x^2 - 5x

x^2 - 5x + 3(x + 5)

<u>Expand:</u>

3(x + 5): 3x + 15

x^2 - 5x + 3x + 15

<u>Add Similar Elements: </u>

-5x + 3x

= -2x

Answer x^2 - 2x + 15 Doesn't Factor

Hope that helps!!! : )

5 0

3 years ago