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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
<h3>
Answer: 2</h3>
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Explanation:
The function f(x) = -4x+1 is the same as y = -4x+1 where y = f(x)
Compare this to y = mx+b and we see the slope here is m = -4
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Now let's find the slope of g(x)
use the slope formula with any two rows you want. I'll pick on the last two rows.
m = (y2-y1)/(x2-x1)
m = (21-9)/(3-1)
m = 12/2
m = 6 is the slope of g(x)
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From here, we add the two slope values
(slope of f)+(slope of g) = -4+6 = 2