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3 years ago

Idk get this questions it says find the varible 4(x+6)=28? does anyone kno this?

Mathematics

2 answers:

otez555 [7]3 years ago

7 0

Answer: hope this helps!

Step-by-step explanation:

Vilka [71]3 years ago

6 0

Answer:

x=1

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation. Pull out like factors. Solve : x-1 = 0

Add 1 to both sides of the equation :

x = 1

You might be interested in

Find slope of the graph 9x-3y=15

LekaFEV [45]

<h3><u>Explanation</u></h3>

Convert the equation into slope-intercept form.

$y = mx + b$

where m = slope and b = y-intercept.

What we have to do is to make the y-term as the subject of equation.

$9x - 3y = 15 \\ 9x - 15 = 3y \\ \frac{9x - 15}{3} = y$

Simplify

$\frac{9x}{3} - \frac{15}{3} = y \\ 3x - 5 = y \\ y = 3x - 5$

From y = mx+b, the slope is 3.

<h3><u>Answer</u></h3>

$\large \boxed {slope = 3}$

4 0

3 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago

25 points!!!!!!!!

podryga [215]

Answer:

A is your answer, my guy

Step-by-step explanation:

4x1=4

3x-1=-3

5x1=5

4+(-3)+5=6

6x1=6

8x-1=-8

6x1=6

6+(-8)+6=4

4x1=4

2x-1=-2

6x1=6

4+(-2)+6=8

8 0

3 years ago

A rectangular block of copper metal has a mass of 1800 grams. The dimensions of the block

Hoochie [10]

Use formula p=m/v
P is density
M is mass
V volume
So you have the volume already now 8x5x4= 160 which is the volume
P= 1800/160 after you divide you get 11.25
The density is 11.25

3 0

3 years ago

Show work and factor ?

kvasek [131]

$5\cdot\dfrac{x^2-2x}{6}:\dfrac{3x-6}{x}=5\cdot\dfrac{x(x-2)}{6}\cdot\dfrac{x}{3x-6}\\\\=5\cdot\dfrac{x(x-2)}{6}\cdot\dfrac{x}{3(x-2)}=\dfrac{5\cdot x\cdot x}{6\cdot3}=\dfrac{5x^2}{18}$

4 0

3 years ago