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Elza [17]
3 years ago
9

A number is multiplied by 16, and that product is added to 8. The sum is equal to the product of 4 and 10. Find the number.

Mathematics
1 answer:
Ymorist [56]3 years ago
5 0

Your sum is 4 times 10, or 40. We want to end up with 40. Subtract 8 because you added 8 before to work backwards. You get 32. Divide by 16 because the opposite of multiplication is division. You would get 2.

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Henry drove 60.2 miles in 7 days how many miles did he drive in 1 day?
igor_vitrenko [27]

Answer:

8.6

Step-by-step explanation:

60.2/7 =8.6

8 0
2 years ago
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Complete the the ratio to convert the units of measure from ounces to grams to ounces ?​
otez555 [7]

Answer:

84 and 5

3x28=84

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7 0
3 years ago
Write each of the following as a function of theta.<br> 1.) sin(pi/4 - theta) 2.) tan(theta+30°)
Paladinen [302]

Step-by-step explanation:

Let x represent theta.

\sin( \frac{\pi}{4} - x )

Using the angle addition trig formula,

\sin(x - y)  =  \sin(x)  \cos(y)  -  \cos(x)  \sin(y)

\sin( \frac{\pi}{4} )  \cos(x)  -  \cos( \frac{\pi}{4} )  \sin(x)

( \frac{ \sqrt{2} }{2})  \cos(x)  -  (\frac{ \sqrt{2} }{2}  )\sin(x)

Multiply one side at a time

Replace theta with x , the answer is

\frac{ \sqrt{2} \cos(x)  }{2}  -  \frac{ \sin(x) \sqrt{2}  }{2}

2. Convert 30 degrees into radian

\frac{30}{1}  \times  \frac{\pi}{180}  =  \frac{\pi}{6}

Using tangent formula,

\tan(x + y)  =  \frac{ \tan(x)  +  \tan(y) }{1 -  \tan(x) \tan(y)  }

\frac{ \tan(x) +  \tan( \frac{\pi}{6} )  }{1 -  \tan(x) \tan( \frac{\pi}{6} )  }

Tan if pi/6 is sqr root of 3/3

\frac{ \tan(x) +  ( \frac{ \sqrt{3} }{3} )  }{1 -  \tan(x)  (\frac{ \sqrt{3} }{3} )  }

Since my phone about to die if you later simplify that,

you'll get

\frac{(3 \tan(x) +  \sqrt{3} )(3 +  \sqrt{3}  \tan(x)  }{3(3 -  \tan {}^{2} (x) }

Replace theta with X.

4 0
2 years ago
A toxic radioactive substance with a density of 7 milligrams per square centimeter is detected in the ventilating ducts of a nuc
uysha [10]
For this case we have an equation of the form:
 y = A * (b) ^ t
 Where,
 A: initial amount
 b: decrease rate
 t: time in years.
 Substituting values we have:
 7 = A * (0.5) ^ ((1/20) * t)
 For t = 45 years we have:
 7 = A * (0.5) ^ ((1/20) * 45) 
 Clearing A:
 A = 7 / ((0.5) ^ ((1/20) * 45))
 A = 33.3
 Answer:
 
the density of the substance when it was deposited 45 years ago was:
 
A = 33.3 milligrams per square centimeter
5 0
3 years ago
2.2+x+(-3.4);x=-2.5
puteri [66]
2.2 - 2.5 - 3.4
-3.7
.................
5 0
3 years ago
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