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tamaranim1 [39]
2 years ago
5

The 10 participants in an experiment had the following reaction times (in milliseconds). 242, 485, 485, 489, 497, 498, 500, 507,

509, 875 Identify all values that are outliers. If there is more than one outlier, separate them with commas. If there are no outliers, click on "None".​
Mathematics
1 answer:
Karolina [17]2 years ago
5 0

Answer:

The outliers are 242 and 875

Step-by-step explanation:

Their numbers are far more away than the other numbers if you had it on a number line. Most of the numbers range from 480-510 (estimation of the range, sorry hehe), so the numbers that seem very far (almost excluded, I guess) would be the ones that are considered the outliers.

242 and 875 are over 100 spaces away from the other numbers, meanwhile 485,485,489,497,498,500,507,509 have shorter spaces in between.

I hope this helped! (Sorry, if it sounds confusing)

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Suppose a box of Cracker Jacks contains one of 5 toy prizes: a small rubber ball, a whistle, a Captain America decoder ring, a r
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11.42 boxes

Step-by-step explanation:

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5 0
3 years ago
When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal. During one
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Answer:

0.82 = 82% probability that at least one party will not order drinks

Step-by-step explanation:

For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.

This means that p = 0.75

During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

6 parties, so n = 6.

Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So

P(X = 6) + P(X < 6) = 1

We want P(X < 6). So

P(X < 6) = 1 - P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.18

P(X < 6) = 1 - P(X = 6) = 1 - 0.18 = 0.82

0.82 = 82% probability that at least one party will not order drinks

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