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Karolina [17]
3 years ago
6

12. Between what two numbers would 9 be located on a number line?

Mathematics
2 answers:
lozanna [386]3 years ago
5 0

Answer:

B

Step-by-step explanation:

1,2,3,4,5,6,7,than 8,9,10

stepan [7]3 years ago
4 0
9 would be located between b. 8 and 10
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Madison is baking party favors she wants to make enough favor so each guest gets the same number of favors she knows there will
iris [78.8K]

Answer:

It would be 24

Step-by-step explanation:

6: 6, 12, 18, 24

8: 8, 16, 24

The least common number is 24, so she should make at least 24.

4 0
3 years ago
How long will it take for an airplane that averages 95 miles an hour to fly 1,710 miles?
zysi [14]
The correct answer is 18 hope that helped♥
5 0
2 years ago
At an important​ meet, Allyson won the​ women's 100 meters in 12.24 seconds. Find her average rate.
otez555 [7]

The rate is 8.17 meters per second

Further explanation:

In order to find the rate we have to divide the distance covered by the woman by the time she covered it in.

Given

Distance=d=100\ meters\\Time=t=12.24\ sec\\So,\\Rate=\frac{d}{t}\\=\frac{100}{12.24}\\=8.17\ ms^{-1}

The rate is 8.17 meters per second

Keywords: Speed, distance

Learn more about speed at:

  • brainly.com/question/4710621
  • brainly.com/question/4767370

#LearnwithBrainly

6 0
3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
3 years ago
Of the Day
Nadya [2.5K]

Answer:

8+8+9+9.. so the answer is 34 yards.

Step-by-step explanation:

6 0
3 years ago
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