Step-by-step explanation:
3/4 × 3/3 = 9/12
3/4 × 2/2 = 6/8
D=4n-2, d+2=4n-2+2, d+2=4n
(d+2)/4=(4n)/4, 1/4d+1/2=n
n=1/4n+1/2
size 3=
n=1/4*3/1=3/4, 3/4+1/2=5/4=1 1/4
size 3=1 1/4
size 6=
n=1/4*6/1=6/4, 6/4+1/2=8/4=2
size 6=2
size 10=
n=1/4*10/1=10/4, 10/4+1/2=12/4=3
size 10=3
Answer:
4m
Step-by-step explanation:
shapes are similar.
purple shape is double the red and 2x2 is four
so the answer is 4m
You know that the length is 2 more than the width. If z is the width then y = z(z+2). I don't see the graph so you will have to scan and look for that y-z relationship.
5. The graph of g(x) is narrower. Both graphs open upward. The vertex of g(x), (0,10), is translated 10 units up from the vertex of f(x) at (0,0)
6. The graph of g(x) is wider. Both graphs open upward. The vertex of g(x), (0,-3) is translated 3 units down from the vertex of f(x) at (0,0)
7.The graph of g(x) is narrower. g(x) opens downward and f(x) opens upward. The vertex of g(x), (0,8) is translated 8 units up from the vertex of f(x) at (0,0).
8. The graph of g(x) is wider. g(x) opens downward and f(x) opens upward. The vertex of g(x), (0,1/4) is translated 1/4 units up from the vertex of f(x) at (0,0).
9. A. h1(t)=-16t^2+400 h2(t)= -16t^2+1600
9. B The graph of h2 is a vertical translation of the graph of h1 : 1200 units up.
9. C sandbag dropped from 400 ft: 5 s
sandbag dropped from 1600 ft: 10 s
