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Norma-Jean [14]
3 years ago
13

The sum of the square root of a number and 6

Mathematics
1 answer:
Anna007 [38]3 years ago
4 0

Answer:

36

Step-by-step explanation:

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Find a quadratic function that includes the set of values below.
Mariana [72]

Answer:

f(x) = -3x^2 + 10x + 3

Step-by-step explanation:

(0,3) (2,11)(3,6)

Using the form ax^2 + bx + c = y

From the first set we know that c = 3

Write an equation for the last two sets

x=2; y=11

a(2^2) + b(2) + 3 = 11

4a + 2b = 11 - 3

4a + 2b = 8

simplify divide by 2

2a + b = 4

and

x=3, y=6

9a + 3b + 3 = 6

9a + 3b = 6 - 3

9a + 3b = 3

simplify divide by 3

3a + b = 1

:

Use elimination to find a

3a + b = 1

2a + b = 4

--------------subtracting eliminate b

a = -3

Find b using the equation 2a + b = 4

2(-3) + b = 4

b = 4 + 6

b = 10

:

The equation: f(x) = -3x^2 + 10x + 3

8 0
3 years ago
Ammeters produced by a manufacturer are marketed under the specification that the standard deviation of gauge readings is no lar
AURORKA [14]

Answer:

0.101

Step-by-step explanation:

Given that :

Standard deviation, s = 0.2

Sample variance, s² = 0.0653

Sample size, n = 10

Population variance = σ² = 0.04

We use the Chi square distribution :

(n - 1)s² / σ²

For P(s² ≥ 0.065)

(n - 1)s² / σ² = (10 - 1)*0.0653 / 0.04

(n - 1)s² / σ² = 0.585 / 0.04 = 14.625

P(s² ≥ 14.625) = 0.101 ( chi squee calculator).

8 0
3 years ago
How do you do this question?
Molodets [167]

Answer:

C. y₂ = (1 + (t/n))²

Step-by-step explanation:

yₙ₊₁ = yₙ + Δt F(tₙ, yₙ)

yₙ₊₁ = yₙ + Δt yₙ

yₙ₊₁ = yₙ + (t/n) yₙ

When n=0:

y₁ = y₀ + (t/n) y₀

y₁ = 1 + (t/n)

When n=1:

y₂ = y₁ + (t/n) y₁

y₂ = 1 + (t/n) + (t/n) (1 + (t/n))

y₂ = 1 + (t/n) + (t/n) + (t/n)²

y₂ = 1 + 2(t/n) + (t/n)²

y₂ = (1 + (t/n))²

4 0
3 years ago
I wrote it down better
Elenna [48]
number one is 280 because 4/2 is 2 + 2 is 4 then you multiply 7 and that is 28 ^ 2 which is 280
4 0
4 years ago
Read 2 more answers
Solve it 7/10+2/3<br>pls explain​
Marat540 [252]

Answer:

1.36

Step-by-step explanation:

4 0
3 years ago
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