Simplify (3x+1)^2(4x-2) hurry

sergiy2304 [10]

Now, keep in mind that, we'll be using 25mile intervals, notice, that at a cost of 200 bucks, it went for 50 miles, now the charges are just for every 25miles only, so, if you drive 30 miles, you pay for 25miles and if you drive for 49 miles, you still only pay for 25 miles, but because 50/25 is 2 intervals, then if you drive for 50 miles, you're paying for 2 intervals of 25miles, not just one.

now, also let's keep in mind that, when the car was driven for 200 miles, that's 200/25 or 8 25mile intervals, so the 25mile charge kicked in 8 times.

$\bf \stackrel{cost}{y}=\stackrel{fixed~charge}{F}+\stackrel{25mile~intervals}{m}\quad \stackrel{25mile~charge}{x}\implies y=F+mx\\\\
-------------------------------\\\\
\begin{cases}
200=F+2x\implies 200-2x=\boxed{F}\\
245=F+8x\\
----------\\
245=\boxed{200-2x}+8x
\end{cases}
\\\\\\
45=6x\implies \cfrac{45}{6}=x\implies \cfrac{15}{2}=x\impliedby 
\begin{array}{llll}
\textit{so the 25mile charge is}\\
\textit{7 bucks and 50cents}
\end{array}
\\\\\\
$

$\bf 200=F+2\left( \frac{15}{2} \right)\implies 200=F+15\implies 185=F
\\\\\\
\textit{and the \underline{fixed charge} is 185 bucks then, let's check for 450}
\\\\\\
\boxed{y=185+\frac{15}{2}x}\qquad 
\begin{cases}
450~miles\\\\
\cfrac{450}{25}\implies 18~\textit{\underline{25mile intervals}}\\\\
x=18
\end{cases}
\\\\\\
y=185+\cfrac{15}{2}\cdot 18\implies y=185+135\implies y=320$

7 0

3 years ago

Daca a + b = 20 si b + c = 30 ,calculati 3 . a + 7 . b + 4 . c ( Dau coroana la cine ma ajuta )

Oduvanchick [21]

It is given that

a+b=20 -------------------- (1)

b+c=30 -----------------------(2)

We have to calculate

3 a + 4 b +7 c

Now multiplying equation(1 )by 3,we get

3 a+ 3 b=60 ----------------------------------(3)

and Multiplying equation( 2) by 4,we get

4 b + 4 c=120 -----------------------------------(4)

Adding expression (3) and (4),we get i.e left hand side of 3 to left hand side of 4 and right hand side of 3 to right hand side of 4.

3 a+ 3 b+ 4 b+ 4 c=60+120

Adding like terms, we get

3 a+ 7 b+ 4 c =180, Which is the required solution.

4 0

3 years ago

Graph x^4-3x^2+x. Identify the x-intercepts and the points where the local maximums and local minimums occur. Determine the inte

Brums [2.3K]

Functions, equations and tables can be represented using graphs

The x-intercepts are: 0, 0.35 and 1.53
The local maximum is at point (0.17, 0.08), and the local minimum is at point (1.13, -1.07)

The expression is given as:

$x^4-3x^2+x$

Rewrite the expression as a function

$f(x) = x^4-3x^2+x$

See attachment for the graph of the function.

<h3>The x-intercepts</h3>

This is the point where the graph cross the x-axis.

From the attached graph, the x-intercepts are: 0, 0.35 and 1.53

<h3>The local maximum</h3>

From the attached graph, the local maximum is at point (0.17, 0.08)

<h3>The local minimum</h3>

From the attached graph, the local minimum is at point (1.13, -1.07)

<h3>Intervals</h3>

The graph increases at interval (-1.30, 0) and (1,13, infinity)
The graph decreases at interval (- infinity, 1.30) and (0.35, 1.13)

Read more about graphs and functions at:

brainly.com/question/13136492

4 0

2 years ago

A common mistake in fielding is not keeping the glove down True or false ?

nata0808 [166]

Answer:

true

Step-by-step explanation:

6 0

3 years ago

A simple random sample of 32 men from a normally distributed population results in a standard deviation of 12.9 beats per minute

krok68 [10]

Answer:

Null Hypothesis, H0 = The pulse rates of men have a standard deviation equal to 10 beats per minute

Alternate Hypothesis, H1 = The pulse rates of men do not have a standard deviation equal to 10 beats per minute

Step-by-step explanation:

The null hypothesis is basically the problem statement i.e

Pulse rates of men have a standard deviation equal to 10 beats per minute

Hence, H0 = The pulse rates of men have a standard deviation equal to 10 beats per minute

The alternate hypothesis will contradict or negate the null hypothesis i.e

H1 = The pulse rates of men do not have a standard deviation equal to 10 beats per minute

4 0

2 years ago