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3 years ago

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The coordinates of the vertices of ΔPQR are (–2, –2), (–6, –2), and (–6, –5). The coordinates of the vertices of ΔPʹQʹRʹ are (−2

, 2), (−6, 2), and (−6, 5). This transformation can be expressed as (x, y) → (x, −y). Is the orientation of ΔPQR the same as the orientation of ΔPʹQʹRʹ? Why or why not? A. No, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis. B. Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis. C. Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the y-axis. D. No, ΔPʹQʹRʹ is a reflection of ΔPQR over the y-axis.

2 answers:

Minchanka [31]3 years ago

5 0

No, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis

mylen [45]3 years ago

5 0

I just took the test. The answer is B.

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What is the equation of the following line written in slope-intercept form?

dolphi86 [110]

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Step-by-step explanation:

Let the equation of the line is,

y - y' = m(x - x')

where (x', y') is a point lying on the given line.

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3 years ago

Pleeeeese help me as fast as you can!!!

Aleonysh [2.5K]

Answer:

A. $y=3x-10$

C. $y+6=3(x-15)$

Step-by-step explanation:

Given:

The given line is $6x+18y=5$

Express this in slope-intercept form $y=mx+b$ , where m is the slope and b is the y-intercept.

$6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}$

Therefore, the slope of the line is $m=-\frac{1}{3}$ .

Now, for perpendicular lines, the product of their slopes is equal to -1.

Let us find the slopes of each lines.

Option A:

$y=3x-10$

On comparing with the slope-intercept form, we get slope as $m_{A}=3$ .

Now, $m\times m_{A}=-\frac{1}{3}\times 3=-1$ . So, option A is perpendicular to the given line.

Option B:

For lines of the form $x=a$ , where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as $m_{C}=3$ .

Now, $m\times m_{C}=-\frac{1}{3}\times 3=-1$ . So, option C is perpendicular to the given line.

Option D:

$3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}$

On comparing with the slope-intercept form, we get slope as $m_{D}=-\frac{1}{3}$ .

Now, $m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}$ . So, option D is not perpendicular to the given line.

8 0

3 years ago